stack-and-queue/stack/implement-stack-using-queues
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2023-12-01
Implement Stack using Queues
描述
Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Notes:
- You must use only standard operations of a queue -- which means only push to back, peek/pop from front, size, and is empty operations are valid.
- Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
分析
可以用两个队列,q
和tmp
,q
存放元素,tmp
用来作中转。
push(x)
,先将x
push 到tmp
,然后把q
中的元素全部弹出来,存入tmp
,最后切换q
和tmp
pop()
,直接将q
的队首元素弹出来即可
该算法push
的算法复杂度是O(n)
, pop
的算法复杂度O(1)
。
另个一个方法是,让pop
是O(n)
, push
是O(1)
,思路很类似,就不赘述了。
代码
// Implement Stack using Queues
class MyStack {
// Push element x onto stack.
// Time Complexity O(n)
public void push(int x) {
tmp.offer(x);
while (!q.isEmpty()) {
final int e = q.poll();
tmp.offer(e);
}
// swap q and tmp
Queue<Integer> temp = tmp;
tmp = q;
q = temp;
}
// Removes the element on top of the stack.
// Time Complexity O(1)
public void pop() {
q.poll();
}
// Get the top element.
public int top() {
return q.peek();
}
// Return whether the stack is empty.
public boolean empty() {
return q.isEmpty();
}
private Queue<Integer> q = new LinkedList<>();
private Queue<Integer> tmp = new LinkedList<>();
}