binary-tree/construction/construct-binary-tree-from-inorder-and-postorder-traversal
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2023-12-01
Construct Binary Tree from Inorder and Postorder Traversal
描述
Given inorder and postorder traversal of a tree, construct the binary tree.
Note: You may assume that duplicates do not exist in the tree.
分析
无
代码
// Construct Binary Tree from Inorder and Postorder Traversal
// 递归,时间复杂度O(n),空间复杂度O(\logn)
public class Solution {
public TreeNode buildTree(int[] inorder, int[] postorder) {
return buildTree(inorder, 0, inorder.length,
postorder, 0, postorder.length);
}
TreeNode buildTree(int[] inorder, int begin1, int end1,
int[] postorder, int begin2, int end2) {
if (begin1 ==end1) return null;
if (begin2 ==end2) return null;
int val = postorder[end2 - 1];
TreeNode root = new TreeNode(val);
int in_root_pos = find(inorder, begin1, end1, val);
int left_size = in_root_pos - begin1;
int post_left_last = begin2 + left_size;
root.left = buildTree(inorder, begin1, in_root_pos,
postorder, begin2, post_left_last);
root.right = buildTree(inorder, in_root_pos + 1, end1,
postorder, post_left_last, end2 - 1);
return root;
}
private static int find(int[] array, int begin, int end, int val) {
for (int i = begin; i < end; ++i) {
if (array[i] == val) return i;
}
return -1;
}
}
// Construct Binary Tree from Inorder and Postorder Traversal
// 递归,时间复杂度O(n),空间复杂度O(\logn)
class Solution {
public:
TreeNode* buildTree(vector<int>& inorder, vector<int>& postorder) {
return buildTree(begin(inorder), end(inorder),
begin(postorder), end(postorder));
}
template<typename BidiIt>
TreeNode* buildTree(BidiIt in_first, BidiIt in_last,
BidiIt post_first, BidiIt post_last) {
if (in_first ==in_last) return nullptr;
if (post_first == post_last) return nullptr;
const auto val = *prev(post_last);
TreeNode* root = new TreeNode(val);
auto in_root_pos = find(in_first, in_last, val);
auto left_size = distance(in_first, in_root_pos);
auto post_left_last = next(post_first, left_size);
root->left = buildTree(in_first, in_root_pos, post_first, post_left_last);
root->right = buildTree(next(in_root_pos), in_last, post_left_last,
prev(post_last));
return root;
}
};