linear-list/array/remove-duplicates-from-sorted-array

Remove Duplicates from Sorted Array

描述

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example, Given input array A = [1,1,2],

Your function should return length = 2, and A is now [1,2].

分析

无

代码

# Remove Duplicates from Sorted Array
# Time Complexity: O(n)，Space Complexity: O(1)
class Solution:
    def removeDuplicates(self, nums: List[int]) -> int:
        if len(nums) == 0:
            return 0

        i = 0
        for j in range(1, len(nums)):
            if nums[j] != nums[i]:
                i += 1
                nums[i] = nums[j]

        return i + 1

// Remove Duplicates from Sorted Array
// Time Complexity: O(n)，Space Complexity: O(1)
public class Solution {
    public int removeDuplicates(int[] nums) {
        if (nums.length == 0) return 0;

        int len = 1;
        for (int i = 1; i < nums.length; i++){
            if (nums[i] != nums[len - 1])
                nums[len++] = nums[i];
        }
        return len;
    }
};

// Remove Duplicates from Sorted Array
// Time Complexity: O(n)，Space Complexity: O(1)
class Solution {
public:
    int removeDuplicates(vector<int>& nums) {
        if (nums.empty()) return 0;

        int len = 1;
        for (int i = 1; i < nums.size(); i++) {
            if (nums[i] != nums[len-1])
                nums[len++] = nums[i];
        }
        return len;
    }
};

相关题目

• Remove Duplicates from Sorted Array II