iOS-Tree-Component

import { PureComponent } from 'react' import { D3 } from "@weapp/ui" let d3: any = null; //辅助函数: 递归获取tree的节点数量 function getCount(parent: any) { var count = 0; if (Array.isArray(parent.children))

body { /* IOS禁止微信调整字体大小 */ -webkit-text-size-adjust: 100% !important; text-size-adjust: 100% !important; -moz-text-size-adjust: 100% !important; }

Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same values. 题目翻译: 给两棵树，写一个函

Given a binary tree, check whether it is a mirror of itself(ie, symmetric around its center) For example, this tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following tree is not.

Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 / \ 2 3 \ 5 All root-to-leaf paths are: ["1->2->5", "1->3"] 题目翻译： 给定一棵二叉树，返回所有从根节点到叶节点的

Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ b

Given inorder and postorder traversal of a tree, construct the binary tree. 要知道如何构建二叉树，首先我们需要知道二叉树的几种遍历方式，譬如有如下的二叉树： 1 --------|------- 2 3 ----|----

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and h