12.13 Fibonacci
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2023-12-01
Question
- lintcode: (366) Fibonacci
Problem Statement
Find the _N_th number in Fibonacci sequence.
A Fibonacci sequence is defined as follow:
- The first two numbers are 0 and 1.
- The i th number is the sum of i-1 th number and i-2 th number.
The first ten numbers in Fibonacci sequence is:
0, 1, 1, 2, 3, 5, 8, 13, 21, 34 ...
Example
Given 1
, return 0
Given 2
, return 1
Given 10
, return 34
Note
The _N_th fibonacci number won't exceed the max value of signed 32-bit integer in the test cases.
题解
斐波那契数列使用递归极其容易实现,其实使用非递归的方法也很容易,不断向前滚动即可。
C++
class Solution{
public:
/**
* @param n: an integer
* @return an integer f(n)
*/
int fibonacci(int n) {
if (n <= 0) return -1;
if (n == 1) return 0;
if (n == 2) return 1;
int fn = 0, fn1 = 0, fn2 = 1;
for (int i = 3; i <= n; i++) {
fn = fn1 + fn2;
fn1 = fn2;
fn2 = fn;
}
return fn;
}
};
Java
class Solution {
/**
* @param n: an integer
* @return an integer f(n)
*/
public int fibonacci(int n) {
if (n <= 0) return -1;
if (n == 1) return 0;
if (n == 2) return 1;
int fn = 0, fn1 = 1, fn2 = 0;
for (int i = 3; i <= n; i++) {
fn = fn1 + fn2;
fn2 = fn1;
fn1 = fn;
}
return fn;
}
}
源码分析
- corner cases
- 初始化 fn, fn1, fn2, 建立地推关系。
- 注意 fn, fn2, fn1的递推顺序。
复杂度分析
遍历一次,时间复杂度为 $$O(n)$$, 使用了两个额外变量,空间复杂度为 $$O(1)$$.