55.2 平衡二叉树
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小牛编辑
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2023-12-01
题目描述
平衡二叉树左右子树高度差不超过 1。
解题思路
// java private boolean isBalanced = true; public boolean IsBalanced_Solution(TreeNode root) { height(root); return isBalanced; } private int height(TreeNode root) { if (root == null || !isBalanced) return 0; int left = height(root.left); int right = height(root.right); if (Math.abs(left - right) > 1) isBalanced = false; return 1 + Math.max(left, right); }