笔试-作业帮-180925

优质
小牛编辑
146浏览
2023-12-01
  • 单选 5,填空 5,编程 2,问答 2
  • 编程不允许跳出页面

1. 点对距离

Python(60%)

  • 试了各种情况,不知道哪里有问题
    
    from math import ceil, floor

def foo(ax, ay, bx, by): d = ((ax - bx)2 + (ay - by)2)**0.5

return d

k = int(input()) n = int(input())

P = [] for _ in range(n): x, y = list(map(float, input().split())) P.append([x, y])

D = [] for i in range(n): for j in range(i+1, n): d = foo(P[i][0], P[i][1], P[j][0], P[j][1]) D.append(d)

D.sort()

N = len(D) - 1

ans = D[ceil(N * (k / 100))]

print(round(ans, 5))


## 2. 扩展型表达式求值

<div align="center"><img src="https://www.xnip.cn/wp-content/uploads/2022/08/20180925203442.png" height="" /></div>
<div align="center"><img src="https://www.xnip.cn/wp-content/uploads/2022/08/20180925203454.png" height="" /></div>
<div align="center"><img src="https://www.xnip.cn/wp-content/uploads/2022/08/20180925203504.png" height="" /></div>

**Python**(57.14%)
- 不能跳出页面,实在不想写这种题,偷鸡过了 57%
```python
def bar(s):
    while "%" in s:
        i = s.find("%")
        j = i - 1
        while s[j].isdigit():
            j -= 1

        s = s[:j+1] + str(int(s[j+1: i]) / 100) + s[i+1:]
    return s

def foo(s):
    if "**" in s or "++" in s or "--" in s:
        return "error"

    s = bar(s)

    try:
        ans = eval(s)
        if isinstance(ans, int):
            return "%d" % ans
        else:
            return "%0.3f" % ans
            #return round(ans, 3)
    except e:
        return "error"

s = input()
ans = foo(s)
#print(bar(s))
print(ans)