查找链接列表的大小(Find size of Linked List)
优质
小牛编辑
127浏览
2023-12-01
实现 (Implementation)
该算法的实现如下 -
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *prev;
struct node *next;
};
struct node *head = NULL;
struct node *last = NULL;
struct node *current = NULL;
//display the list
void printList() {
struct node *ptr = head;
printf("\n[head] <=>");
//start from the beginning
while(ptr != NULL) {
printf(" %d <=>",ptr->data);
ptr = ptr->next;
}
printf(" [last]\n");
}
//Create Linked List
void insert(int data) {
// Allocate memory for new node;
struct node *link = (struct node*) malloc(sizeof(struct node));
link->data = data;
link->prev = NULL;
link->next = NULL;
// If head is empty, create new list
if(head==NULL) {
head = link;
return;
}
current = head;
// move to the end of the list
while(current->next!=NULL)
current = current->next;
// Insert link at the end of the list
current->next = link;
last = link;
link->prev = current;
}
void sizeof_list() {
int size = 0;
struct node *link;
if(head==NULL) {
printf("\n Size of list is %d\n", size);
return;
}
link = head;
while(link != NULL) {
link = link->next;
size++;
}
printf("\n Size of list is %d\n", size);
}
int main() {
insert(10);
insert(20);
insert(30);
insert(1);
insert(40);
insert(56);
printList();
sizeof_list();
return 0;
}
输出 (Output)
该方案的产出应该是 -
[head] <=> 10 <=> 20 <=> 30 <=> 1 <=> 40 <=> 56 <=> [last]
Size of list is 6