现在,我们将看到该计划的实际执行情况 -
#include <stdio.h>
int main() {
char s[] = "TajMahal"; // String Given
int i = 0;
int vowels = 0; // Vowels counter
int consonants = 0; // Consonants counter
while(s[i++] != '\0') {
if(s[i] == 'a' || s[i] == 'e' || s[i] == 'i' || s[i] == 'o' || s[i] == 'u' )
vowels++;
else
consonants++;
}
printf("'%s' contains %d vowels and %d consonants.", s, vowels, consonants);
return 0;
}
该计划的输出应为 -
'TajMahal' contains 3 vowels and 5 consonants.