结合两个循环链表(Combine Two Circular Linked List)
优质
小牛编辑
123浏览
2023-12-01
实现 (Implementation)
该算法的实现如下 -
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *next;
};
struct node *even = NULL;
struct node *odd = NULL;
struct node *list = NULL;
//Create Linked List
void insert(int data) {
// Allocate memory for new node;
struct node *link = (struct node*) malloc(sizeof(struct node));
struct node *current;
link->data = data;
link->next = NULL;
if(data%2 == 0) {
if(even == NULL) {
even = link;
even->next = link;
return;
} else {
current = even;
while(current->next != even)
current = current->next;
// Insert link at the end of the list
current->next = link;
link->next = even;
}
} else {
if(odd == NULL) {
odd = link;
odd->next = link;
return;
} else {
current = odd;
while(current->next != odd) {
current = current->next;
}
// Insert link at the end of the list
current->next = link;
link->next = odd;
}
}
}
void display(struct node *head) {
int temp;
struct node *ptr = head;
if(head == NULL) {
printf("Linked List not initialized");
return;
} else if(head->next == head) {
printf("%d", head->data);
return;
}
printf("[head] =>");
while(ptr->next != head) {
printf(" %d =>",ptr->data);
ptr = ptr->next;
}
printf(" %d =>",ptr->data);
printf(" [head]\n");
}
void combine() {
struct node *elink, *olink;
list = even;
elink = list;
while(elink->next!= even) {
elink = elink->next;
}
elink->next = odd;
olink = odd;
while(olink->next!= odd) {
olink = olink->next;
}
olink->next = even;
}
int main() {
int i;
for(i = 1; i <= 10; i++)
insert(i);
printf("Even : ");
display(even);
printf("Odd : ");
display(odd);
combine();
printf("Combined List :\n");
display(list);
return 0;
}
输出 (Output)
该方案的产出应该是 -
Even : [head] => 2 => 4 => 6 => 8 => 10 => [head]
Odd : [head] => 1 => 3 => 5 => 7 => 9 => [head]
Combined List :
[head] => 2 => 4 => 6 => 8 => 10 => 1 => 3 => 5 => 7 => 9 => [head]