在C中搜索字符串的程序（Program to search strings in C）

实现 (Implementation)

现在，我们将看到该计划的实际执行情况 -

#include <stdio.h>
#include <string.h>
int main() {
   char s1[] = "Beauty is in the eye of the beholder";
   char s2[] = "the";
   int n = 0;
   int m = 0;
   int times = 0;
   int len = strlen(s2);      // contains the length of search string
   while(s1[n] != '\0') {
      if(s1[n] == s2[m]) {     // if first character of search string matches
         // keep on searching
         while(s1[n] == s2[m]  && s1[n] !='\0') {
            n++;
            m++;
         }
         // if we sequence of characters matching with the length of searched string
         if(m == len && (s1[n] == ' ' || s1[n] == '\0')) {
            // BINGO!! we find our search string.
            times++;
         }
      } else {            // if first character of search string DOES NOT match
         while(s1[n] != ' ') {        // Skip to next word
            n++;
            if(s1[n] == '\0')
            break;
         }
      }
      n++;
      m=0;  // reset the counter to start from first character of the search string.
   }
   if(times > 0) {
      printf("'%s' appears %d time(s)\n", s2, times);
   } else {
      printf("'%s' does not appear in the sentence.\n", s2);
   }
   return 0;
}

输出 (Output)

该计划的输出应为 -

'the' appears 2 time(s)