结合两个链接列表(Combine Two Linked List)
优质
小牛编辑
125浏览
2023-12-01
实现 (Implementation)
该算法的实现如下 -
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *next;
};
struct node *even = NULL;
struct node *odd = NULL;
struct node *list = NULL;
//Create Linked List
void insert(int data) {
// Allocate memory for new node;
struct node *link = (struct node*) malloc(sizeof(struct node));
struct node *current;
link->data = data;
link->next = NULL;
if(data%2 == 0) {
if(even == NULL) {
even = link;
return;
} else {
current = even;
while(current->next != NULL)
current = current->next;
// Insert link at the end of the list
current->next = link;
}
} else {
if(odd == NULL) {
odd = link;
return;
} else {
current = odd;
while(current->next!=NULL)
current = current->next;
// Insert link at the end of the list
current->next = link;
}
}
}
void display(struct node *head) {
struct node *ptr = head;
printf("[head] =>");
while(ptr != NULL) {
printf(" %d =>",ptr->data);
ptr = ptr->next;
}
printf(" [null]\n");
}
void combine() {
struct node *link;
list = even;
link = list;
while(link->next!= NULL) {
link = link->next;
}
link->next = odd;
}
int main() {
int i;
for(i = 1; i <= 10; i++)
insert(i);
printf("Even : ");
display(even);
printf("Odd : ");
display(odd);
combine();
printf("Combined List :\n");
display(list);
return 0;
}
输出 (Output)
该方案的产出应该是 -
Even : [head] => 2 => 4 => 6 => 8 => 10 => [null]
Odd : [head] => 1 => 3 => 5 => 7 => 9 => [null]
Combined List :
[head] => 2 => 4 => 6 => 8 => 10 => 1 => 3 => 5 => 7 => 9 => [null]