从链接列表中删除项目(Remove an Item from Linked List)

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小牛编辑
126浏览
2023-12-01

实现 (Implementation)

该算法的实现如下 -

#include <stdio.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *prev;
   struct node *next;
};
struct node *head = NULL;
struct node *last = NULL;
struct node *current = NULL;
//display the list
void printList() {
   struct node *ptr = head;
   printf("\n[head] <=>");
   //start from the beginning
   while(ptr != NULL) {        
      printf(" %d <=>",ptr->data);
      ptr = ptr->next;
   }
   printf(" [last]\n");
}
void print_backward() {
   struct node *ptr = last;
   printf("\n[last] <=>");
   //start from the beginning
   while(ptr != NULL) {        
      printf(" %d <=>",ptr->data);
      ptr = ptr->prev;
   }
   printf(" [head]\n");
}
//Create Linked List
void insert(int data) {
   // Allocate memory for new node;
   struct node *link = (struct node*) malloc(sizeof(struct node));
   link->data = data;
   link->prev = NULL;
   link->next = NULL;
   // If head is empty, create new list
   if(head==NULL) {
      head = link;
      return;
   }
   current = head;
   // move to the end of the list
   while(current->next!=NULL)
      current = current->next;
   // Insert link at the end of the list
   current->next = link;
   last = link;
   link->prev = current;
}
void remove_data(int data) {
   int pos = 0;
   struct node *pre_node;
   if(head==NULL) {
      printf("Linked List not initialized");
      return;
   } 
   if(head->data == data) {
      if(head->next != NULL) {
         head->next->prev = NULL;
         head = head->next;
         return;
      } else {
         head = NULL;
         printf("List is empty now");
         return;
      }
   } else if(head->data != data && head->next == NULL) {
      printf("%d not found in the list\n", data);
      return;
   }
   current = head;
   while(current->next != NULL && current->data != data) {
      pre_node = current;
      current = current->next;
   }        
   if(current->data == data) {
      pre_node->next = pre_node->next->next;
      if(pre_node->next != NULL) {          // link back
         pre_node->next->prev = pre_node;
      } else
         last = pre_node;
      free(current);
   } else
      printf("%d not found in the list.", data);
}
int main() {
   insert(10);
   insert(20);
   insert(30);
   insert(1);
   insert(40);
   insert(56); 
   printList();
   remove_data(20);
   printList();
   print_backward();
   return 0;
}

输出 (Output)

该方案的产出应该是 -

[head] <=> 10 <=> 20 <=> 30 <=> 1 <=> 40 <=> 56 <=> [last]
[head] <=> 10 <=> 30 <=> 1 <=> 40 <=> 56 <=> [last]
[last] <=> 56 <=> 40 <=> 1 <=> 30 <=> 10 <=> [head]