用C语言计算程序中有多少个奇偶数

Question

程序要求用户输入数字，直到总数大于30为止。此外，用户必须计算有多少个数字是偶数，有多少是奇数。我可以得到问题的第一部分，但我在计算部分遇到了问题。

即

总计是0
请输入一个整数：20
总计是20
您有1个偶数和0个奇数。

#include <iostream>
#include <string>
using namespace std;
int main (){
   int integer;
   int total = 20;
   int even_count = 0;
   int odd_count = 0;
   cout << "Total is 0" << endl;
   cout << "Please enter an integer: ";
   cin >> integer;
   cout << integer << endl;
   while ( total <= 30){
      cout << "Total is " << total << endl;
      cout << "Please enter an integer: ";
      cin >> integer;
      cout << integer << endl;
      total = integer + total;  
   }
   if (integer % 2 == 0) {
         even_count = even_count + 1;
      }
   if (integer % 2 != 0){
         odd_count = odd_count + 1;
      }
   cout << "You had " << even_count << " even numbers and "; 
   cout << odd_count << " odd numbers.";
   cout << endl;
   return 0;
}

Answer 1

此代码应适用于：

#include <iostream>
#include <string>
using namespace std;
int main (){
   int integer=0;
   int total = 0;
   int even_count = 0;
   int odd_count = 0;
   cout << "Total is " << total << endl;
   while ( total <=30 && integer <=30){
      cout << "Please enter an integer: ";
      cin >> integer;
      total = integer + total;  
      if(total <=30){
        cout << "Total is " << total << endl;
      }
      if (integer % 2 == 0) {
        even_count = even_count + 1;
      }
      if (integer % 2 == 1){
        odd_count = odd_count + 1;
      }
   }   
   cout << "You had " << even_count << " even numbers and " << odd_count << 
" odd numbers." << endl;   
}

这是一个示例输出：总计为0请输入一个整数：25总计为25请输入一个整数：5总计为30请输入一个整数：1您有0个偶数和3个奇数