Python碰撞检测

Question

我已经尝试添加冲突检测一段时间了，但似乎做不到...

要绘制地图，我只需使用x，y坐标：

from setup import *

treeload = "Images/tree.jpg"
tree = pygame.image.load(treeload).convert_alpha()

class drawtree:

     def __init__(self, x, width, step1, y, height, step2):

        self.x = x
        self.y = y
        self.width = width
        self.height = height
        self.step1 = step1
        self.step2 = step2

    def draw(self):

        for x in range(self.x, self.x+self.width, self.step1):
            for y in range(self.y, self.y+self.height, self.step2):
                window.blit(tree, (x,y))

t1 = drawtree(100, 100, 20, 0, 90, 30)
t2 = drawtree(400, 300, 20, 0, 90, 30)
t3 = drawtree(100, 270, 20, 450, 150, 30)
t4 = drawtree(400, 300, 20, 450, 150, 30)

trees = [t1, t2, t3 ,t4]

使用这种方法，我想出了这种检测：

from setup import *
from drawtree import *
from player import *

def wall_detect(x1, y1, w1, h1, x2, y2, w2, h2):
    if (x2+w2>=x1>=x2 and y2+h2>=y1>=y2):
        return True
    elif (x2+w2>=x1+w1>=x2 and y2+h2>=y1>=y2):
        return True
    elif (x2+w2>=x1>=x2 and y2+h2>=y1+h1>=y2):
        return True
    elif (x2+w2>=x1+w1>=x2 and y2+h2>=y1+h1>=y2):
        return True
    else:
        return False

我一直在尝试使用for循环遍历树来检测玩家（一个矩形）是否穿过树，但我想不出任何东西。

我已经试过了

    for i in trees:
        collision = wall_detect(player.x, player.y, player.width, player.height, i.x, i.y, i.width, i.height)
    player.update(collision)

如果碰撞=true，player.update（碰撞）将矩形更改为红色，如果为false，将矩形变为黑色。

我已尝试使用for和if，例如：

for i in trees:
        if wall_detect(player.x, player.y, player.width, player.height, i.x, i.y, i.width, i.height) == wall_detect(player.x, player.y, player.width, player.height, t1.x, t1.y, t1.width, t1.height):
            collision = wall_detect(player.x, player.y, player.width, player.height, t1.x, t1.y, t1.width, t1.height)
           player.update(collision)

        if wall_detect(player.x, player.y, player.width, player.height, i.x, i.y, i.width, i.height) == wall_detect(player.x, player.y, player.width, player.height, t2.x, t2.y, t2.width, t2.height):
            collision = wall_detect(player.x, player.y, player.width, player.height, t2.x, t2.y, t2.width, t2.height)
            player.update(collision)

等但这不起作用，它只适用于with 1 if语句，其余语句则被注释掉。

Answer 1

一个问题是该循环的性质：

for i in trees:
    collision = wall_detect(player.x, player.y, player.width, player.height, i.x, i.y, i.width, i.height)
player.update(collision)

假设玩家与树中的第一棵树相撞。然后碰撞将为True，但循环的将继续。因此，只有当玩家与列表中的最后一棵树碰撞时，碰撞才会成为True。有多种方法可以解决这个问题。

# Change the assignment to check if it is already true
collision = False
for i in trees:
    collision = collision or wall_detect(...

或

# Exit the loop if it is true
for i in trees:
    collision = wall_detect(...)
    if collision:
        break

或

# Turn it into a function that returns when it is true
def walls_detect(player, trees):
    for tree in trees:
        if wall_detect(...):
            return True
    return False

...
# Call it like this
player.update(walls_detect(player, trees))

在我看来，发生碰撞时的逻辑是正确的，但也可以简化很多：

def wall_detect(x1, y1, w1, h1, x2, y2, w2, h2):
    return (x2+w2>=x1>=x2 or x2+w2>=x1+w1>=x2) and (y2+h2>=y1>=y2 or y2+h2>=y1+h1>=y2)