在pygame中旋转矩形(不是图像)

Question

在pygame中，我对我的程序中的所有矩形使用pygame.draw.rect（屏幕、颜色、矩形）。我希望能够将这些矩形旋转到任何角度。我已经看到了以下旋转IMAGES的代码，但我的问题是RECTANGLES。

pygame.transform.rotate(image, angle)

但是我正在使用矩形，我没有可以旋转的图像或“表面”。当我尝试旋转矩形时

rect = pygame.draw.rect(screen, self.color, self.get_rectang())
rotatedRect = pygame.transform.rotate(rect, self.rotation)
screen.blit(rotatedRect)

这就给出了类型错误：必须是pygame。表面上看，这不是游戏。在带有.rotate（）的行上使用Rect

我的问题是，如何在pygame中旋转a并显示矩形＜code＞（x，y，w，h），而不是图像。

这是“潜在重复”的链接帖子不是重复的。一个答案解释了旋转矩形的后果，另一个使用代码旋转图像。

Answer 1

一个更复杂的快速替换版本，您可以在其中为矩形定义任意旋转中心点 - 甚至在矩形之外（在python3中测试）：

    def rectRotated( surface, color, pos, fill, border_radius, rotation_angle, rotation_offset_center = (0,0), nAntialiasingRatio = 1 ):
        """
        - rotation_angle: in degree
        - rotation_offset_center: moving the center of the rotation: (-100,0) will turn the rectangle around a point 100 above center of the rectangle,
                                             if (0,0) the rotation is at the center of the rectangle
        - nAntialiasingRatio: set 1 for no antialising, 2/4/8 for better aliasing
        """
        nRenderRatio = nAntialiasingRatio
        
        sw = pos[2]+abs(rotation_offset_center[0])*2
        sh = pos[3]+abs(rotation_offset_center[1])*2

        surfcenterx = sw//2
        surfcentery = sh//2
        s = pg.Surface( (sw*nRenderRatio,sh*nRenderRatio) )
        s = s.convert_alpha()
        s.fill((0,0,0,0))
        
        rw2=pos[2]//2 # halfwidth of rectangle
        rh2=pos[3]//2

        pg.draw.rect( s, color, ((surfcenterx-rw2-rotation_offset_center[0])*nRenderRatio,(surfcentery-rh2-rotation_offset_center[1])*nRenderRatio,pos[2]*nRenderRatio,pos[3]*nRenderRatio), fill*nRenderRatio, border_radius=border_radius*nRenderRatio )
        s = pygame.transform.rotate( s, rotation_angle )        
        if nRenderRatio != 1: s = pygame.transform.smoothscale(s,(s.get_width()//nRenderRatio,s.get_height()//nRenderRatio))
        incfromrotw = (s.get_width()-sw)//2
        incfromroth = (s.get_height()-sh)//2
        surface.blit( s, (pos[0]-surfcenterx+rotation_offset_center[0]+rw2-incfromrotw,pos[1]-surfcentery+rotation_offset_center[1]+rh2-incfromroth) )
        

Answer 2

import pygame as py  

# define constants  
WIDTH = 500  
HEIGHT = 500  
FPS = 30  

# define colors  
BLACK = (0 , 0 , 0)  
GREEN = (0 , 255 , 0)  

# initialize pygame and create screen  
py.init()  
screen = py.display.set_mode((WIDTH , HEIGHT))  
# for setting FPS  
clock = py.time.Clock()  

rot = 0  
rot_speed = 2  

# define a surface (RECTANGLE)  
image_orig = py.Surface((100 , 100))  
# for making transparent background while rotating an image  
image_orig.set_colorkey(BLACK)  
# fill the rectangle / surface with green color  
image_orig.fill(GREEN)  
# creating a copy of orignal image for smooth rotation  
image = image_orig.copy()  
image.set_colorkey(BLACK)  
# define rect for placing the rectangle at the desired position  
rect = image.get_rect()  
rect.center = (WIDTH // 2 , HEIGHT // 2)  
# keep rotating the rectangle until running is set to False  
running = True  
while running:  
    # set FPS  
    clock.tick(FPS)  
    # clear the screen every time before drawing new objects  
    screen.fill(BLACK)  
    # check for the exit  
    for event in py.event.get():  
        if event.type == py.QUIT:  
            running = False  

    # making a copy of the old center of the rectangle  
    old_center = rect.center  
    # defining angle of the rotation  
    rot = (rot + rot_speed) % 360  
    # rotating the orignal image  
    new_image = py.transform.rotate(image_orig , rot)  
    rect = new_image.get_rect()  
    # set the rotated rectangle to the old center  
    rect.center = old_center  
    # drawing the rotated rectangle to the screen  
    screen.blit(new_image , rect)  
    # flipping the display after drawing everything  
    py.display.flip()  

py.quit()  

Answer 3

在此处查看第二个答案：围绕另一个点旋转一个点 （2D）

我认为矩形在方向上只能是水平或垂直的。你需要定义角并旋转它们，然后在它们之间进行绘制和填充。

另一种方法是上课

class myRect(pygame.Surface):
    def __init__(self, parent, xpos, ypos, width, height):
      super(myRect, self).__init__(width, height)
      self.xpos = xpos
      self.ypos = ypos
      self.parent = parent

    def update(self, parent):
      parent.blit(self, (self.xpos, self.ypos))

    def rotate(self, angle):
      #(your rotation code goes here)

并使用它，因为这样您就可以使用转换函数旋转它。