用集合
list(set(l))
用字典
l1 = ['b','c','d','b','c','a','a'] l2 = {}.fromkeys(l1).keys() print l2
用字典并保持顺序
l1 = ['b','c','d','b','c','a','a'] l2 = list(set(l1)) l2.sort(key=l1.index) print l2
列表推导式
l1 = ['b','c','d','b','c','a','a'] l2 = [] [l2.append(i) for i in l1 if not i in l2]
sorted排序并且用列表推导式.
l = ['b','c','d','b','c','a','a'] [single.append(i) for i in sorted(l) if i not in single] print single
