12 找零问题
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小牛编辑
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2023-12-01
#coding:utf-8
#values是硬币的面值values = [ 25, 21, 10, 5, 1]
#valuesCounts 钱币对应的种类数
#money 找出来的总钱数
#coinsUsed 对应于目前钱币总数i所使用的硬币数目
def coinChange(values,valuesCounts,money,coinsUsed):
#遍历出从1到money所有的钱数可能
for cents in range(1,money+1):
minCoins = cents
#把所有的硬币面值遍历出来和钱数做对比
for kind in range(0,valuesCounts):
if (values[kind] <= cents):
temp = coinsUsed[cents - values[kind]] +1
if (temp < minCoins):
minCoins = temp
coinsUsed[cents] = minCoins
print ('面值:{0}的最少硬币使用数为:{1}'.format(cents, coinsUsed[cents]))
思路: http://blog.csdn.net/wdxin1322/article/details/9501163
方法: http://www.cnblogs.com/ChenxofHit/archive/2011/03/18/1988431.html