如何使用ooxml apache poi通过精确坐标旋转90度来创建弯曲连接器

Question

最近，我正在与Apache POI合作，我在旋转弯曲的连接器时遇到了一个问题，需要精确定位。我想将bent connector表示为形状之间的流动级别，我在可视化方面有一个问题，所以我的基本问题是在使用ooxml apache poi绘制形状连接器时，它被描述如下

我期待下面的结果，有人能提供一些建议来解决这个问题吗

ooxml和apache poi PPT

Answer 1

为了获得您想要的弯曲连接，默认的BENT_CONNECTOR_3需要水平翻转，然后逆时针旋转90度。

下面的完整示例说明了这一点。注意代码中的注释。

import java.io.FileOutputStream;

import org.apache.poi.xslf.usermodel.*;
import org.apache.poi.sl.usermodel.*;
import org.openxmlformats.schemas.presentationml.x2006.main.*;
import org.openxmlformats.schemas.drawingml.x2006.main.*;

import java.awt.Rectangle;
import java.awt.geom.Rectangle2D;
import java.awt.Color;

public class CreatePPTXConnectorShapes {
    
 private static XSLFConnectorShape createConnector(XSLFSlide slide, XSLFAutoShape shape1, XSLFAutoShape shape2) {
  XSLFConnectorShape connector = slide.createConnector();
  connector.setShapeType(ShapeType.BENT_CONNECTOR_3); // bent connector having one handle
  connector.setAnchor(new Rectangle2D.Double( //connector is diagonal in a rectangle
   shape1.getAnchor().getCenterX(), // top left x of that rectangle is center x position of shape1
   shape1.getAnchor().getMaxY(), // top left y of that rectangle is bottom y of shape1
   shape2.getAnchor().getCenterX()-shape1.getAnchor().getCenterX(), // width of that rectanle is center x of shape2 minus center x of shape1
   shape2.getAnchor().getY()-shape1.getAnchor().getMaxY() // height of that rectanle is top y of shape2 minus bottom y of shape1
   ));
  // the rectangle needs to be flipped horizontally as the default bent connector having one handle is like so:
  // ----+
  //     |
  //     +----
  connector.setFlipHorizontal(true);
  // now it is like so:
  //     +----
  //     |
  // ----+
  // and needs to be rotated 90 deg counter-clockwise 
  connector.setRotation(-90.00);
  // now it is like so:
  // |
  // +---+
  //     |
  // now we fix the connecting points
  CTConnector ctConnector = (CTConnector)connector.getXmlObject();
  CTNonVisualConnectorProperties cx = ctConnector.getNvCxnSpPr().getCNvCxnSpPr();
  CTConnection start = cx.addNewStCxn();
  start.setId(shape1.getShapeId());
  start.setIdx(2); // connecting point 2 is center of bottom edge
  CTConnection end = cx.addNewEndCxn();
  end.setId(shape2.getShapeId());
  end.setIdx(0); // connecting point 0 is center of top edge

  return connector;  
 }

 public static void main(String[] args) throws Exception {

  XMLSlideShow slideShow = new XMLSlideShow();

  XSLFSlide slide = slideShow.createSlide();

  XSLFAutoShape shape1 = slide.createAutoShape();
  shape1.setShapeType(ShapeType.RECT);
  shape1.setFillColor(Color.BLUE);
  shape1.setAnchor(new Rectangle(50, 50, 150, 50));
  
  XSLFAutoShape shape2 = slide.createAutoShape();
  shape2.setShapeType(ShapeType.RECT);
  shape2.setFillColor(Color.BLUE);
  shape2.setAnchor(new Rectangle(150, 200, 150, 50));
  
  // create connector 
  XSLFConnectorShape connector1 = createConnector(slide, shape1, shape2);
 
  FileOutputStream out = new FileOutputStream("CreatePPTXConnectorShapes.pptx");
  slideShow.write(out);
  out.close();
 }
}

它产生：

很明显，如果包含连接件的矩形（作为对角线）是正方形，那么旋转就很容易。这就是为什么上面的代码可以工作，并显示了主要原则。我将把它留在答案中，以免一开始就让它复杂化，并且有代码显示当包含连接线的矩形（作为对角线）不是正方形时的问题。

如果包含连接件作为对角线的矩形不是正方形，则需要考虑旋转时左上角位置和尺寸的变化来设置锚定。我们有TL1，旋转后所需的位置，可以根据形状的位置和尺寸来计算。我们需要TL0，旋转前的左上角点。对于尺寸，需要考虑旋转后宽度和高度的交换。

           TL0*-------+
              |   .   |
              |   .   |
              |   .   |
 TL1*---------------------------+
    |         |   .   |         |
    h- - - - - - -+rp- - - - - -|
    |         |   .   |         |
    +-------------w-------------+
              |   .   |
              |   .   |
              |   .   |
              +-------+
we have TL1, which can get calculated from the shape position and dimension
TL1X, TL1Y, w: width, h: height
we need TL0, which is the top left point before rotating (rp = rotation point)
TL0X = TL1X + (w/2 - h/2) = TL1X + (w - h) / 2
TL0Y = TL1Y - (w/2 - h/2) = TL1Y - (w - h) / 2
width and height simply get swapped

如果形状2位于形状1的右下方，则以下操作应该有效。接头从形状1的下边缘中心到形状2的上边缘中心。

import java.io.FileOutputStream;

import org.apache.poi.xslf.usermodel.*;
import org.apache.poi.sl.usermodel.*;
import org.openxmlformats.schemas.presentationml.x2006.main.*;
import org.openxmlformats.schemas.drawingml.x2006.main.*;

import java.awt.Rectangle;
import java.awt.geom.Rectangle2D;
import java.awt.Color;

public class CreatePPTXConnectorShapes2 {
    
 private static XSLFConnectorShape createConnector(XSLFSlide slide, XSLFAutoShape shape1, XSLFAutoShape shape2) {
  XSLFConnectorShape connector = slide.createConnector(); 
  // if shape2 is on the right below shape1; connector is from center of bottom edge of shape1 to center of top edge of shape2
  if (shape2.getAnchor().getX() >= shape1.getAnchor().getCenterX() && shape2.getAnchor().getY() >= shape1.getAnchor().getMaxY()) {
   connector.setShapeType(ShapeType.BENT_CONNECTOR_3); // bent connector having one handle
   // the rectangle needs to be flipped horizontally as the default bent connector having one handle is like so:
   // ----+
   //     |
   //     +----
   connector.setFlipHorizontal(true);
   // now it is like so:
   //     +----
   //     |
   // ----+
   // and needs to be rotated 90 deg counter-clockwise 
   connector.setRotation(-90.00);
   // now it is like so:
   // |
   // |
   // +---+
   //     |
   //     |
   // set the anchor after rotating
   //connector is diagonal in a rectangle
   //before rotating it would be:
   double topLeftX = shape1.getAnchor().getCenterX(); // top left x of that rectangle is center x position of shape1
   double topLeftY = shape1.getAnchor().getMaxY(); // top left y of that rectangle is bottom y of shape1
   double width = shape2.getAnchor().getCenterX()-shape1.getAnchor().getCenterX(); // width of that rectanle is center x of shape2 minus center x of shape1
   double height = shape2.getAnchor().getY()-shape1.getAnchor().getMaxY(); // height of that rectanle is top y of shape2 minus bottom y of shape1
   //considering the rotation it is:
   topLeftX = topLeftX + (width - height) / 2;
   topLeftY = topLeftY - (width - height) / 2;
   double w = width;
   width = height;
   height = w;  
   connector.setAnchor(new Rectangle2D.Double(topLeftX, topLeftY, width, height));
   // now it is like so:
   // |
   // +-------+
   //         |  
   // now we fix the connecting points
   CTConnector ctConnector = (CTConnector)connector.getXmlObject();
   CTNonVisualConnectorProperties cx = ctConnector.getNvCxnSpPr().getCNvCxnSpPr();
   CTConnection start = cx.addNewStCxn();
   start.setId(shape1.getShapeId());
   start.setIdx(2); // connecting point 2 is center of bottom edge
   CTConnection end = cx.addNewEndCxn();
   end.setId(shape2.getShapeId());
   end.setIdx(0); // connecting point 0 is center of top edge
  }

  return connector;  
 }

 public static void main(String[] args) throws Exception {

  XMLSlideShow slideShow = new XMLSlideShow();

  XSLFSlide slide = slideShow.createSlide();

  XSLFAutoShape shape1 = slide.createAutoShape();
  shape1.setShapeType(ShapeType.RECT);
  shape1.setFillColor(Color.BLUE);
  shape1.setAnchor(new Rectangle(50, 50, 150, 50));
  
  XSLFAutoShape shape2 = slide.createAutoShape();
  shape2.setShapeType(ShapeType.RECT);
  shape2.setFillColor(Color.BLUE);
  shape2.setAnchor(new Rectangle(150, 200, 150, 50));
  
  XSLFAutoShape shape3 = slide.createAutoShape();
  shape3.setShapeType(ShapeType.RECT);
  shape3.setFillColor(Color.BLUE);
  shape3.setAnchor(new Rectangle(400, 200, 150, 50));
  
  // create connectors
  XSLFConnectorShape connector1 = createConnector(slide, shape1, shape2);
  XSLFConnectorShape connector2 = createConnector(slide, shape1, shape3);
 
  FileOutputStream out = new FileOutputStream("CreatePPTXConnectorShapes.pptx");
  slideShow.write(out);
  out.close();
 }
}

它产生：

免责声明：正如我在这里的所有代码示例一样，这不是一个在生产环境中使用的适用于所有产品的解决方案，而只是一个展示原则的工作草案。为了创造一个可以有效使用的解决方案，你必须自己努力。