Cloropeth（）得到了一个意想不到的关键字参数'位置'

Question

我在做一个程序，制作一些关于新冠病毒病例的图表，遇到了一些问题。代码应该显示三个图形，但只显示两个。有人能帮我找出这里的错误吗？

错误：TypeError:choropleth（）获取了意外的关键字参数“location”

代码：

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import seaborn as sns
import plotly.express as px

data = pd.read_csv('covid.csv')
data.drop(['FIPS','Admin2','Last_Update','Province_State','Combined_Key'],axis=1,inplace=True)
data.rename(columns={'Country_Region':'Country'},inplace=True)
world = data.groupby('Country')['Confirmed', 'Active', 'Recovered', 'Deaths'].sum().reset_index()
tp = world.sort_values(by=['Confirmed'], ascending = False).head(20)
plt.figure(figsize=(12,10))
plot = sns.barplot(tp['Confirmed'], tp['Country'])

for i, (value, name) in enumerate(zip(tp['Confirmed'], tp['Country'])):
    plot.text(value, i-0.05, f'{value:,.0f}', size = 10)
plt.show()


top_5 = world.sort_values(by=['Confirmed'], ascending=False).head()
plt.figure(figsize=(15, 5))
confirmed = sns.barplot(top_5['Confirmed'], top_5['Country'], color = 'red', label = 'Confirmed')
recovered = sns.barplot(top_5['Recovered'], top_5['Country'], color = 'green', label = 'Recovered')

for i, (value, name) in enumerate(zip(top_5['Confirmed'], top_5['Country'])):
    confirmed.text(value, i-0.05, f'{value:,.0f}', size = 9)

for i, (value, name) in enumerate(zip(top_5['Confirmed'], top_5['Country'])):
    recovered.text(value, i-0.05, f'{value:,.0f}', size = 9)
    
plt.legend(loc=4)
plt.show()
figure = px.choropleth(world, location = 'Country',locationmode='Country names',color='Confirmed',
                       hover_name = 'Country',color_continuous_scale='tealgrn',
                       range_color = [1,1000000],title = 'Coutries with Confirmed Cases ')
figure.show()

Answer 1

检查您的loropeth（）模型是否有位置

Answer 2

来自阴谋。表示choropleth（），plotly。表示choropleth（）具有参数位置而不是位置。