Java骰子游戏-选择谁开始一个基于掷骰子和轮流的游戏

Question

提示：“写一个程序对着电脑玩猪游戏。在每个回合，当前玩家将掷出一对骰子并累积点数。目标是在你的对手之前达到100分或更多。（为了测试的目的，使用30点而不是100点）如果在任何回合中，玩家掷出一个1，则该回合积累的所有点数都将被没收，骰子的控制权将转移到另一个玩家身上。如果玩家在一个回合中滚动两个1，则该玩家失去迄今为止积累的所有点数，控制权转移到另一个玩家身上。玩家可以在每次掷骰后自愿交出骰子的控制权。因此，玩家必须决定再掷一次（当猪），冒着丢分的风险，或者放弃对骰子的控制，可能会让另一个玩家赢。计算机将掷硬币来选择第一个玩家“

我的问题：我得到的程序输出，要么电脑或播放器是第一个基于硬币翻转。然而，我将如何实际提示程序运行一个选择的人首先开始的方法，然后我将如何在每个回合结束时在计算机和播放器之间切换？顺便说一句，我知道这段代码是不完整的，但我希望我的问题是有意义的。

import java.util.*;
public class NavaiPigGame
{
   public static final int POINT = 30;
   public static final int FORFEIT_POINTS = 20;
   public static void main(String[] args)
   {
      Scanner input = new Scanner(System.in);
      Random rand = new Random();
      play(rand,input);
   }
   // desription of game
   public static void description()
   {
      System.out.println("***********************************************************************************");
      System.out.println("Write a program to play the pig game against the computer. At each turn, the current player will");
      System.out.println("roll a pair of dice and accumulates points. The goal is to reach to 100 or more points before your");
      System.out.println("opponent does. (For the testing purposes use 30 instead of 100 points) If, on any turn, the player");
      System.out.println("rolls a 1, all the points accumulated for that round are forfeited and the control of the dice");
      System.out.println("moves to the other player. If the player rolls two 1s in one turn, the player loses all the points");
      System.out.println("accumulated thus far are forfeited and the control moves to the other player. The player may");
      System.out.println("voluntarily turn over the control of the dice after each roll. Therefore player must decide to roll");
      System.out.println("again (be a pig) and risk losing points, or relinquish control of the dice, possibly allowing the");
      System.out.println("other player to win. Computer is going to flip a coin to choose the first player");
      System.out.println("***********************************************************************************");
      System.out.println("lets start the fun");
   }
   //flips a coin and decides who starts the game
   public static String flipCoin(Random rand)
   {
      int coin = rand.nextInt(2);
      String comp = "";
      switch (coin)
      {
         case 0: comp = "heads";
                 break;
         case 1: comp = "tails";   
                 break;
      }
      return comp;
   }
   public static int rollDice(Random rand)
   {
      int dice1 = rand.nextInt(6)+1;
      int dice2 = rand.nextInt(6)+1;
      System.out.println("Dice 1: " +dice1);
      System.out.println("Dice 2: " +dice2);
      return dice1+dice2;     
   }
   // select a random name of the computer via arrays
   public static String nameComputer(Random rand)
   {
      int name = rand.nextInt(10);
      String compName = "";
      switch (name)
      {
         case 0: compName = "Lisa";
                 break;
         case 1: compName = "Kathy";
                 break;
         case 2: compName = "Hali";
                 break;
         case 3: compName = "Jack";
                 break;
         case 4: compName = "Alex";
                 break;
         case 5: compName = "Max";
                 break;
         case 6: compName = "Jill";
                 break;
         case 7: compName = "James";
                 break;
         case 8: compName = "Martha";
                 break;
         case 9: compName = "Lauren";
                 break;
      }
      return compName;
   }
   public static void play(Random rand, Scanner input)
   {
      int playerScores = 0;
      int playerTotal = 0;
      int computerScores = 0;
      int computerTotal = 0;
      boolean gameOver = false
      boolean turnOver = false
      description();
      String compName = nameComputer(rand);
      System.out.println("Hi my name is " + compName);
      System.out.print("What is your name? ");
      String name = input.nextLine();
      System.out.println("Hi " + name + ", I am flipping the coin to determine who goes first");
      System.out.print("press any key to start the game. ");
     input.nextLine(); 
     String flip = flipCoin(rand);
     int turn;
     if (flip.equals("heads"))
     {
        turn = 1;
        System.out.println("You are going to start the game");
     }
     else
     {
        turn = 0;
        System.out.println(compName + " is going to start the game");
     } 
   }
}

Answer 1

创建：

• 处理玩转（掷骰子、计算点等）的playturn（int turn）函数（1用于玩家，0用于计算机）
• 检查是否有赢家的布尔函数。示例：isWinner（int player）（同样，1表示播放器，0表示计算机）

第一次在if()else状态中使用该函数，如下所示：

if (flip.equals("heads"))
{
    turn = 1;
    System.out.println("You are going to start the game");
    playTurn(turn);
 }
 else
 {
    turn = 0;
    System.out.println(compName + " is going to start the game");
    playTurn(turn);
 } 

 do {
     if(turn == 1){
         turn = 0;
         playTurn(turn);
     }else{
         turn == 1;
         playTurn(turn);
     }
  while ( !isWinner(1)|| !isWinner(0) );

这不是很好的设计，但它应该希望给你一个关于下一步该做什么的提示。