Java骰子游戏分配困难

Question

我是Java的初学者，所以我不太懂。我在大学的课程中学习Java，我正在为作业做骰子游戏。

Player 1 rolls a 3 and a 3
Player 1 now has 6 Player 1 gets to roll again Player 1 rolls a 5 and a 1
Player 1 now has 12
Player 2 rolls a 5 and a 1
Player 2 now has 6
Player 1 rolls a 5 and a 6
Player 1 now has 23
Player 1 wins with a total of 23"

import java.util.*;

public class Main
{

    public static void main(String[] args)
    {
        Scanner scan = new Scanner(System.in);
        Random generator = new Random();

        int dice1;
        int dice2;
        int sum;
        boolean endTurn = false;
        boolean endGame = false;
        int totalsum1 = 0;
        int totalsum2 = 0;

        //PLAYER 1

        do
            {

            dice1 = generator.nextInt(6) + 1;
            dice2 = generator.nextInt(6) + 1;
            sum = dice1 + dice2;
            totalsum1 += sum;

            System.out.println("Player 1 rolls a " + dice1 + " and a " + dice2);
            System.out.println("Player 1 now has " + sum);

            if (dice1 != dice2)
            {

                //endTurn = true;
                while (totalsum1 < 75) ;

            } else
                {

                System.out.println("Player 1 gets to roll again");

                dice1 = generator.nextInt(6) + 1;
                dice2 = generator.nextInt(6) + 1;

                System.out.println("Player 1 rolls a " + dice1 + " and a " + dice2);
                System.out.println("Player 1 now has " + (totalsum1 + dice1 + dice2));

                }

            if (totalsum1 >= 75 && !(totalsum2 >= 75))
            {
                System.out.println("Player 1 wins with a total of " + totalsum1);
                //endGame = true;
                break;

            }

            //PLAYER

            dice1 = generator.nextInt(6) + 1;
            dice2 = generator.nextInt(6) + 1;
            sum = dice1 + dice2;
            totalsum2 += sum;

            System.out.println("Player 2 rolls a " + dice1 + " and a " + dice2);
            System.out.println("Player 2 now has " + sum);

            if (dice1 != dice2)
            {

                endTurn = true;
                while (totalsum2 < 75) ;

            } else
                {

                        System.out.println("Player 2 gets to roll again");

                        dice1 = generator.nextInt(6) + 1;
                        dice2 = generator.nextInt(6) + 1;

                        System.out.println("Player 2 rolls a " + dice1 + " and a " + dice2);
                        System.out.println("Player 2 now has " + (totalsum2 + dice1 + dice2));

                }

                    if (totalsum2 >= 75 && !(totalsum1 >= 75))
                    {
                        System.out.println("Player 2 wins with a total of " + totalsum2);
                        endGame = true;
                        break;

                    }
                } while (totalsum1 < 75 && totalsum2 < 75);
        }
    }

Answer 1

我将展开我的评论，并使用您已经存在的代码来帮助您开始使用player类：

class Player {
  private static final Random generator = new Random();

  private static final int WIN_SCORE = 75;

  private final String name;
  private int totalSum;
  private final int winScore;

  public Player( String name, int winScore ) {
    super();
    this.name = name;
    this.winScore = winScore;
  }

  public boolean executeTurn() {

    boolean rollAgain = roll();

    while( rollAgain ) {
      System.out.println( name + " gets to roll again" );
      rollAgain = roll();
    }

    //returns true if the player won
    return totalSum >= winScore;
  }

  private boolean roll() {
    int dice1 = generator.nextInt( 6 ) + 1;
    int dice2 = generator.nextInt( 6 ) + 1;
    totalSum += dice1 + dice2;

    System.out.println( name + " rolls a " + dice1 + " and a " + dice2 );
    System.out.println( name + " now has " + totalSum );

    //return true if he may roll again
    return dice1 == dice2;
  }

  public String getName() {
    return name;
  }
}

我做了一些更改，最显著的是方法roll()和executeTurn()。它们使用您已经存在的代码，但是为了简化重路由，它们进行了一些拆分。roll()将返回true，如果允许玩家再次滚动，并且executeTurn()将让玩家滚动，直到不再有双打（您可能必须检查中间的获胜条件，但我现在在回合结束时保留了这个条件）。

executeTurn()现在将返回true是获胜的玩家，所以您所要做的就是循环并替换玩家，直到其中一个玩家获胜。

int winScore = 75;
Player p1 = new Player("Player 1", winScore );
Player p2 = new Player("Player 2", winScore );
Player current = null;

//might be dangerous if due to a bug no player would ever win but we'll leave it simple for now
//we just loop forever and break the loop from the inside whenever a player won
while ( true ) {
  //p1 has had his turn so now it's p2's turn
  if( current == p1 ) {
    current = p2;
  } else {
    current = p1;
  }

  boolean won = current.executeTurn();

  //the player won so end the loop
  if( won ) {
    break;
  }
}

//since we didn't change the current player after he's won we just can get his name
System.out.println(current.getName() + " won");

正如您所看到的，这从玩家1开始，然后只是在两者之间交替。他们轮流，直到其中一个赢了，然后我们结束循环，宣布获胜者。

这可以扩展到2个以上的玩家，并通过使用扫描器更改传递给玩家的WinScore，但我将留给您作为练习。：）