pygame仅在鼠标在游戏窗口上活动时更新？

Question

刚刚开始使用pyplay（python 2.7，win7，i3），并在这里查看教程：http://www.pygame.org/docs/tut/intro/intro.html

当我运行代码示例时：

import sys, pygame
pygame.init()

size = width, height = 320, 240
speed = [2, 2]
black = 0, 0, 0

screen = pygame.display.set_mode(size)

ball = pygame.image.load('ball.bmp')
ballrect = ball.get_rect()

while 1:
    for event in pygame.event.get():
        if event.type == pygame.QUIT: sys.exit()

        ballrect = ballrect.move(speed)
        if ballrect.left < 0 or ballrect.right > width:
            speed[0] = -speed[0]
        if ballrect.top < 0 or ballrect.bottom > height:
            speed[1] = -speed[1]

        screen.fill(black)
        screen.blit(ball, ballrect)
        pygame.display.flip()

...从空闲或powershell，只有当鼠标在游戏窗口上移动时，游戏窗口才会更新。我原以为球只会自己弹来弹去。这种鼠标位置相关的性能是不是因为pygame/SDL处理图形模式的方式？它与硬件有关吗？有没有办法通过代码来提高性能？我想让pygame成为大家熟知的游戏，这似乎。。。古怪的非常感谢。

编辑：

while 1:
    for event in pygame.event.get():
        if event.type == pygame.QUIT: sys.exit()

    ballrect = ballrect.move(speed)
    if ballrect.left < 0 or ballrect.right > width:
        speed[0] = -speed[0]
    if ballrect.top < 0 or ballrect.bottom > height:
        speed[1] = -speed[1]

    screen.fill(black)
    screen.blit(ball, ballrect)
    pygame.display.flip()

Answer 1

您在函数中有更新代码！像这样把它搬出去，它就会起作用。

while 1:
    for event in pygame.event.get():
        if event.type == pygame.QUIT: sys.exit()

        ballrect = ballrect.move(speed)
        if ballrect.left < 0 or ballrect.right > width:
            speed[0] = -speed[0]
        if ballrect.top < 0 or ballrect.bottom > height:
            speed[1] = -speed[1]

    screen.fill(black)
    screen.blit(ball, ballrect)
    pygame.display.flip()