我如何在Android中计算谷歌地图v2上到折线点的当前距离？

Answer 1

我用这种方法做标记。假设你有组成折线的点的经纬度，这应该是：

public class MapUtils {

public static float distBetween(LatLng pos1, LatLng pos2) {
    return distBetween(pos1.latitude, pos1.longitude, pos2.latitude,
            pos2.longitude);
}

/** distance in meters **/
public static float distBetween(double lat1, double lng1, double lat2, double lng2) {
    double earthRadius = 3958.75;
    double dLat = Math.toRadians(lat2 - lat1);
    double dLng = Math.toRadians(lng2 - lng1);
    double a = Math.sin(dLat / 2) * Math.sin(dLat / 2)
            + Math.cos(Math.toRadians(lat1))
            * Math.cos(Math.toRadians(lat2)) * Math.sin(dLng / 2)
            * Math.sin(dLng / 2);
    double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
    double dist = earthRadius * c;

    int meterConversion = 1609;

    return (float) (dist * meterConversion);
}
}

为了确定道路是否在转弯，我会研究向量之间的欧几里得角（x是当前位置，y是折线点）

只需采取您目前的位置和一个拉特LNG从前面的一些距离为此。

Location currentLocation; // obtained somewhere in your code
LatLng polylinePoint; // a point further ahead

double cLat = currentLocation.getLatitude();
double cLon = currentLocation.getLongitude();

double pLat = polylinePoint.latitude;
double pLon = polylinePoint.longitude;

double angle = Math.acos(
        (cLat*pLat+cLon+pLon) / norm(cLat,cLon)*norm(pLat,cLon));

private double norm(double x, double y) {
    return Math.sqrt(Math.pow(x, 2)*Math.pow(y, 2));    
}