用struct实现两个矩阵的相加

Question

g++ -O2 -Wall program.cpp -o program

产出：

在文件include from/usr/include/C++/4.8/IOStream:39:0、from proy3.cpp:2:/usr/include/C++/4.8/ostream:548:5:注意：模板std::basic_ostream&std::operator<<(std::basic_ostream&,const无符号char*)操作符<<(Basic_ostream&__out,const无符号char*_s)^/usr/include/c++/4.8/ostream:548:5:注意：模板参数扣减/替换失败:proy3.cpp:51:30:注意：::BASIC_OSTREAM'cin<<&M2.x[i][j]；

代码：

# include < cstdio >
# include < iostream >


typedef struct Matrix
{
    int row, column;
            int x[20][20];
};

Matrix M1,M2;

int main（）{

cout << "Insert size rows: Mat[a]";
cin >> M1.row);

cout << "Insert size of columns Mat[a]";
cin >> M1.column;


cout << "Insert size of rows Mat[b]";
cin >> M2.row;

cout << "Insert size of columns Mat[b]";
cin >> M2.column;

int i, j;

   // Matrix x

    for(i = 0; i <= M1.row; i++)
{
        for(j = 0; j <= M1.column; j++)
        {
        cout << "Insert number for matrix X : \n";
        cin >> M1.x[i][j]
        }
}

       // Matrix y

    for(i = 0; i <= M2.row; i++)
{
        for(j = 0; j <= M2.column; j++)
        {
        cout << "Insert number for matrix Y : \n";
        cin << M2.x[i][j];
        }
}

// Matrix X + Matrix Y

for(i = 0; i <= M1.row; i++)
{
    for(j = 0; j < M1.column; j++)
    {
        cout <<"The sum of " << M1.x[i][j] << " + " <<  M2.x[i][j] << " = " << M1.x[i][j] +  M2.x[i][j] << endl;
    }
}
return 0;

}

Answer 1

  for(i = 0; i <= M2.M1.row; i++)
 {
    for(j = 0; j <= M2.M1.column; j++)
    {
    cout << "Insert number for matrix Y : \n";
    cin << &M2.M1.y[i][j];   
    }
  }

您没有试图访问的m2.m1.y这样的元素。另外，为什么要在M2中声明M1呢？您可以只有一个结构和两个实例

struct matrix
{
    int row,column;
    int X[20][20];
};
struct matrix M1,M2;

现在可以输入这两个矩阵了。

另外，您必须使用CIN>>A而不是CIN>>&A。

 cin >> M2.x[i][j];
    ^^^^