一个简单的推箱子小游戏
单昊穹
推箱子小游戏
一个很简单的推箱子小游戏，增加了退回一步的功能（实现方式很传统，通过标记上一个按键的方向，逆向将地图变换）
#include <stdio.h>
#include <conio.h>//输入
#include <windows.h>//清屏的头文件
int flag;
int old = 0;//记录上一次的方向
int tui;
int s;
int sum=0;
int map[9][11] = {
{0,1,1,1,1,1,1,1,1,1,0},
{0,1,0,0,0,1,0,0,0,1,0},
{0,1,0,0,3,3,3,3,0,1,0},
{0,1,0,3,0,3,0,3,0,1,1},
{0,1,0,0,0,2,0,0,3,0,1},
{1,1,0,1,1,1,1,0,3,0,1},
{1,0,4,4,4,4,4,0,0,0,1},
{1,0,4,4,4,4,4,0,0,1,1},
{1,1,1,1,1,1,1,1,1,1,0}
};
void winlose()//判断输赢
{
int i, j;
int k = 0;
for (i = 0; i < 9; i++)
{
for (j = 0; j < 11; j++)
{
if (map[i][j] == 3)
k++;
}
}
if (k == 0)
{
printf("恭喜你获得了胜利\n");
printf("一共走了 %d 步",sum/2);
flag = 0;
}
}
void draw_map()
{
int i, j;
winlose();
for (i = 0; i < 9; i++)
{
for (j = 0; j < 11; j++)
{
switch (map[i][j])
{
case 0:
printf(" ");//空地
break;
case 1:
printf("■");//箱子
break;
case 2:
printf("人");
break;
case 3:
printf("※");//箱子
break;
case 4:
printf("终");
break;
case 6:
printf("♀");//人加终点
break;
case 7:
printf("★");//箱子加终点
break;
}
}
printf("\n");
}
}
void move()
{
int i, j,row , lie;
for (row = 0; row < 9; row++)
{
for (lie = 0; lie < 11; lie++)
{
if (map[row][lie] == 2||map[row][lie]==6)
{
i = row;
j = lie;
}
}
}
tui = _getch();
if (tui == '1')
{
if (old == 1)
{
if (s == 0)
{
if (map[i + 1][j] == 0 || map[i + 1][j] == 4)
{
map[i + 1][j] += 2;
map[i][j] -= 2;
}
}
else if (s == 1)
{
map[i - 1][j] -= 3;
map[i][j] += 1;
map[i + 1][j] += 2;
}
}
else if (old == 2)
{
if (s == 0)
{
if (map[i - 1][j] == 0 || map[i - 1][j] == 4)
{
map[i - 1][j] += 2;
map[i][j] -= 2;
}
}
else
{
map[i + 1][j] -= 3;
map[i][j] += 1;
map[i - 1][j] += 2;
}
}
else if (old == 3)
{
if (s == 0)
{
if (map[i][j + 1] == 0 || map[i][j + 1] == 4)
{
map[i][j + 1] += 2;
map[i][j] -= 2;
}
}
else
{
map[i][j - 1] -= 3;
map[i][j] += 1;
map[i][j + 1] += 2;
}
}
else if (old == 4)
{
if (s == 0)
{
if (map[i][j - 1] == 0 || map[i][j - 1] == 4)
{
map[i][j - 1] += 2;
map[i][j] -= 2;
}
}
else
{
map[i][j + 1] -= 3;
map[i][j] += 1;
map[i][j - 1] += 2;
}
}
}
else
{//与getchar()有区别的是：getchar()输入一个字符后需要回车来进行下一个字符的输入，
//比较麻烦 ，getch()则不需要回车就能连续输入多个字符。
switch (tui) {
case 'w'://分析所有可以移动的情况：（以上移为例）
// 1.人的上面是空地；
// 2.人的上面是终点位置；
// 3.人的上面是箱子
//3.1.箱子的上面是空地；
//3.2.箱子的上面是终点位置。
case 'W':
case 72:
old = 1;
if (map[i - 1][j] == 0 || map[i - 1][j] == 4)
{
s = 0;
map[i - 1][j] += 2;
map[i][j] -= 2;
}
else if (map[i - 1][j] == 3 || map[i - 1][j] == 7)
{
s = 1;
if (map[i - 2][j] == 0 || map[i - 2][j] == 4)
{
map[i - 2][j] += 3;
map[i - 1][j] -= 1;
map[i][j] -= 2;
}
}
break;
case 's':
case 'S':
case 80:
old = 2;
if (map[i + 1][j] == 0 || map[i + 1][j] == 4)
{
s = 0;
map[i + 1][j] += 2;
map[i][j] -= 2;
}
else if (map[i + 1][j] == 3 || map[i + 1][j] == 7)
{
s = 1;
if (map[i + 2][j] == 0 || map[i + 2][j] == 4)
{
map[i + 2][j] += 3;
map[i + 1][j] -= 1;
map[i][j] -= 2;
}
}break;
case 'A':
case 'a':
case 75:
old = 3;
if (map[i][j - 1] == 0 || map[i][j - 1] == 4)
{
s = 0;
map[i][j - 1] += 2;
map[i][j] -= 2;
}
else if (map[i][j - 1] == 3 || map[i][j - 1] == 7)
{
s = 1;
if (map[i][j - 2] == 0 || map[i][j - 2] == 4)
{
map[i][j - 2] += 3;
map[i][j - 1] -= 1;
map[i][j] -= 2;
}
}break;
case 'd':
case 'D':
case 77:
old = 4;
if (map[i][j + 1] == 0 || map[i][j + 1] == 4)
{
s = 0;
map[i][j + 1] += 2;
map[i][j] -= 2;
}
else if (map[i][j + 1] == 3 || map[i][j + 1] == 7)
{
s = 1;
if (map[i][j + 2] == 0 || map[i][j + 2] == 4)
{
map[i][j + 2] += 3;
map[i][j + 1] -= 1;
map[i][j] -= 2;
}
}break;
}
}
}
int main(void)
{
flag = 1;
while (flag)
{
system("cls");
printf("开始游戏\n\n");
printf("按数字 1 键可以退回，但只能退回一步\n\n");
if(tui=='1')
printf("下次小心啊，（^_^）\n\n");
draw_map();
move();
sum++;
}
return 0;
}
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