简单的猜数字游戏。C

Question

我一直在尝试制作一个简单的游戏，计算机生成一个随机数，你试着猜它。它还存储了你“尝试”的猜测量。

但是，当我运行该程序时，它只是打印：“让我们玩游戏。我会想到一个数字 1-100。试着猜猜。

这是我的代码：

    #include <iostream>

    int main()

    {
        using namespace std;

        int the_number;
        int guess;
        int tries;

        the_number = rand() % 101 + 1;

        cout << "Let's play a game!";
        cout << "I will think of a number 1-100. Try to guess it.";
        cout << endl;
        cin >> guess;

        for (tries = 0; tries++;)
        {
            if (guess == the_number)
            {
                cout << "You guessed it!";
                cout << "And it only took you: " << tries;
            }
            else if (guess < the_number)
            {
                cout << "Higher";
                tries++;
            }


            else if (guess > the_number)
            {
                cout << "Lower";
                tries++;
            }

            else
                cout << "That's not even in range!";
            return 0;





    }



}

我不明白为什么这不起作用，有人能解释一下为什么不起作用吗？

Answer 1

您应该在这里使用＜code＞而＜/code＞循环，而不是＜code＞用于＜/code>：

while (the_number != guess)
{
    //
    //
}

并尝试使用新的

#include <random>

std::random_device rd;

std::default_random_engine engine(rd());
std::uniform_int_distribution<int> uniform_dist(1, 100);

the_number = uniform_dist(engine);

Answer 2

您可以定义几个变量，使您的代码更易于理解，如下所示：

#include <iostream>
using namespace std;

int main()
{char EndGame = 'N';
    int MyNumber = 150 , playerguess;
    cout << "I have a number between 1 and 100.\nCan you guess my number ??\nPlease type your first guess.\n?" << endl;

    do{
        cin >> playerguess;
    if (playerguess > MyNumber) {
        cout << " Too High. Try again." << endl;

    }

    else if (playerguess == MyNumber) {
        cout << "Excellent ! You Got It ! \n If you want to exit press Y" << endl;
        cin >> EndGame;
        break;

    }
    else {
        cout << " Too Low. Try again." << endl;
    }
    } while (1);
return 0;
}

这将使数字等于150。每次用户输入一个值时，控制台将确定它是更高、更低还是等于这个数字。

如果您想每次都将其设为随机数，您可以简单地使用

Answer 3

你的程序在“让我们玩个游戏”之后不打印任何东西的原因。我会想出一个数字1-100。你猜猜看。”就是您编写< code>for循环的方式。

for ( tries = 0; tries++; )

在不执行任何操作的情况下中断循环，因为尝试计算结果为0。

此外，为了使程序正常工作，需要添加更多代码来读取猜测。类似下面的代码应该可以工作。

   for (tries = 0; ; tries++)
   {
      if (guess == the_number)
      {
         cout << "You guessed it!";
         cout << "And it only took you " << tries << " tries.\n";
         break;
      }
      else if (guess < the_number)
      {
         cout << "Higher";
         cin >> guess;
      }

      else if (guess > the_number)
      {
         cout << "Lower";
         cin >> guess;
      }
   }