从数组中删除所有特定副本[副本]

Question

我有两个不同的数组，我想删除第二个数组中第一个数组元素的所有副本。我尝试了一些拼接和索引的方法，但没能实现。查看了一些其他帖子，但找不到我真正想要的。下面是一个示例代码。谢谢大家。

let container = [1, 2, 2, 2, 3, 3, 3, 4, 5];
let removing = [2, 3];


function func(container, removing){
  let result = //i want to write a function there which will remove all duplicates of "removing" from "container".
  return result; // result = [1, 4, 5]
}

Answer 1

你可以这样做，

function func(container, removing){
  let result = container.filter(data => {
                   if(removing.indexOf(data) < 0) return true;})
  return result; // result = [1, 4, 5]
}

Answer 2

使用筛选与包括：

let container = [1, 2, 2, 2, 3, 3, 3, 4, 5];
let removing = [2, 3];


function func(container, removing){
  let result = container.filter(e => !removing.includes(e));
  return result;
}

console.log(func(container, removing));

Answer 3

这你去

let container = [1, 2, 2, 2, 3, 3, 3, 4, 5];
let removing = [2, 3];


let difference = (a, b) => a.filter(x => !b.includes(x));

console.log(difference(container, removing))