石头布剪刀在返回前做了一个额外的循环，不知道该如何修复

Question

如果你向下滚动到我的游戏循环注释，我有我的函数Game（）。我希望我的游戏在玩家点数或电脑点数达到5时停止循环。它们在if-else语句中都有单独的返回。我的问题是，它不是添加最后一点然后返回“you win”或“you lose”语句，而是再次提示用户，然后返回“you win”或“you lose”。它不会干扰点，但是这是一个我仍然想要修复的小错误。

当我查看我的代码时，我知道我的警报（playound）在我的game继续html" target="_blank">声明之后，我想知道它的位置是否是它再次发生然后返回我的结果的原因。如果这是问题，我如何继续我的游戏循环，直到有人达到5分？如果这不是问题，那么我可以得到关于我应该尝试什么方法的提示吗？谢谢。

let playerPoints = 0;
let computerPoints = 0;


// Computer Selection
function computerPlay() {

    const compAnswer = options[Math.floor(Math.random() * options.length)];
    return compAnswer;
}
// One round of the game results

function playRound(playerSelection, computerSelection) {

    let rock = options[0];
    let paper = options[1];
    let scissors = options[2];
    let youWin = "You Win! ";
    let youLose = "You Lose! ";
    let rockWin = "Rock beats scissors.";
    let scissorWin = "Scissors beats paper.";
    let paperWin = "Paper beats rock.";
    let tie = "It's a tie, no points added."
    if (playerSelection === computerSelection) {
        console.log(playerPoints, computerPoints);
        return tie;
    } else if (playerSelection === rock && computerSelection === scissors) {
        playerPoints = playerPoints + 1;
        console.log(playerPoints, computerPoints);
        return youWin + rockWin;

    } else if (playerSelection === rock && computerSelection == paper) {
        computerPoints = computerPoints + 1;
        console.log(playerPoints, computerPoints);
        return youLose + paperWin;

    } else if (playerSelection === scissors && computerSelection === rock) {
        computerPoints = computerPoints + 1;
        console.log(playerPoints, computerPoints)
        return youLose + rockWin;
    } else if (playerSelection === scissors && computerSelection === paper) {
        playerPoints = playerPoints + 1;
        console.log(playerPoints, computerPoints)
        return youWin + scissorWin;
    } else if (playerSelection === paper && computerSelection === rock) {
        playerPoints = playerPoints + 1;
        console.log(playerPoints, computerPoints);
        return youWin + paperWin;
    } else if (playerSelection === paper && computerSelection === scissors) {
        computerPoints = computerPoints + 1;
        console.log(playerPoints, computerPoints);
        return youLose + scissorWin;
    } else {
        console.log(playerPoints, computerPoints);
        return "I'm sorry please try another answer"
    }


};
//Game loop
function game() {

    let gameContinue = true;
    while (gameContinue) {
        const computerSelection = computerPlay();
        const playerSelection = prompt("Choose your weapon");

        if (playerPoints < 5 && computerPoints < 5) {
            gameContinue = true;
            alert(playRound(playerSelection, computerSelection));
        } else if (playerPoints === 5) {
            gameContinue = false;
            console.log("You win");
        } else if (computerPoints === 5) {
            gameContinue = false;
            console.log("You Lose")
        }
    }

};

game();

Answer 1

这是代码中的逻辑错误。我很高兴告诉你答案，但也许我可以给你一个提示，让你可以从中学习。

想象玩家刚刚赢得了他的第5场比赛。

把你的手指放在这行代码上：

 alert(playRound(playerSelection, computerSelection));

在这一点上，我们知道playerPoints是5。

在用户解除警报对话框后，警报函数返回后，接下来运行哪行代码？

这里还有另一个提示：gameContinue在警报语句返回后保持为true。您希望运行哪行代码将其设置为false？