简单的Javascript游戏，重复功能。（新手问题）

Question

我是一个新的编码和堆栈溢出，所以对我容易。我将非常感谢一些帮助尝试解释我的目标到一个html5网站上的一个游戏的函数脚本。脚本的功能是提供一个模拟赛马的比赛结果，随后可以在RPG中使用。

选择你的选择，击中比赛和胜利者是选择与几率有关的胜利者。

var gen_number = getRoll(serverSeed, clientSeed, $nonceValue);

var winnerNumber = 0;
if(gen_number < 836)
  winnerNumber = 1;
else if(gen_number < 2172)
  winnerNumber = 2;
else if(gen_number < 2840)
  winnerNumber = 3;
else if(gen_number < 4109)
  winnerNumber = 4;
else if(gen_number < 5766)
  winnerNumber = 5;
else if(gen_number < 7837)
  winnerNumber = 6;
else if(gen_number < 8589)
  winnerNumber = 7;
else
  winnerNumber = 8;

var status = '';
if($selectedRange.includes('' + winnerNumber)) {
  document.getElementById('winner_lose').innerHTML = winnerNumber + " Wins";
  status = 'Win';

任何帮助都将是感激的，这是一个有趣的概念，学习与！

提前谢谢你。

Answer 1

下面是一个基于您的代码的工作示例，它演示了一种简单的方法，即每卷一分，第一到10名被宣布为获胜者：

const serverSeed = 0, clientSeed = 0, $nonceValue = 0;  // stubbed values
const getRoll = () => Math.random() * 10000;  // stubbed function

const getPointWinner = () => {
  const gen_number = getRoll(serverSeed, clientSeed, $nonceValue);

  if (gen_number < 836)
    return 0;
  if (gen_number < 2172)
    return 1;
  if (gen_number < 2840)
    return 2;
  if (gen_number < 4109)
    return 3;
  if (gen_number < 5766)
    return 4;
  if (gen_number < 7837)
    return 5;
  if (gen_number < 8589)
    return 6;
  return 7;
}

let raceWon = false;
const pointsWon = [0, 0, 0, 0, 0, 0, 0, 0];
while (!raceWon) {
  const pointWinner = getPointWinner();  // get the winner for this point
  pointsWon[pointWinner]++;  // award the point
  raceWon = pointsWon[pointWinner] >= 10;  // race won if point winner has 10 points
}

// pointsWon can be used to print out the winner, final order, won by x lengths, etc.
console.log(pointsWon);  // prints the array containing the points won

const winner = pointsWon.indexOf(10) + 1;  // + 1 since pointsWon uses a zero-based index
console.log('winner:', winner);  // prints the first to 10 points