在不同数组列表中循环

Question

联机-节点1,节点2离线-节点3,节点4未知-节点5,节点6

private String nodeStatus() {

    List<Node> onlineNodes = new ArrayList<Node>();
    List<Node> offlineNodes = new ArrayList<Node>();
    List<Node> unknownNodes = new ArrayList<Node>();

    for(Node n : getNodes()){

        if (n.isRunning() == RunningType.ONLINE) {
            onlineNodes.add(n);
        }

        if (n.isRunning() == RunningType.OFFLINE) {
            offlineNodes.add(n);
        }

        if (n.isRunning() == RunningType.UNKNOWN) {
            unknownNodes.add(n);
        }
    }

    for (Node element : <online,offline,unknown>) {
        System.out.println(element);
    }

}

Answer 1

如果我理解正确的话，您想要的是使用第4个列表在1for-loopW/O上迭代3个列表，实现此目的的方法是：

import java.util.*;

public class MultipleArraysLooping {
    public static void main (String args[]) {
        List <String> list1 = new ArrayList <String>();
        List <String> list2 = new ArrayList <String>();
        List <String> list3 = new ArrayList <String>();
        fillLists(list1, list2, list3);
        iterateLists(list1, list2, list3);
    }

    public static void fillLists(List <String> list1,
        List <String> list2, List <String> list3) {
        list1.add("item1 on list1");
        list1.add("item2 on list1");
        list1.add("item3 on list1");

        list2.add("item1 on list2");
        list2.add("item2 on list2");
        list2.add("item3 on list2");
        list2.add("item4 on list2");
        list2.add("item5 on list2");

        list3.add("item1 on list3");
        list3.add("item2 on list3");
    }

    public static void iterateLists(List <String> list1,
        List <String> list2, List <String> list3) {
        int size = 0;
        if (list1.size() > list2.size()) {
            if (list1.size() > list3.size()) {
                size = list1.size();
            } else {
                size = list3.size();
            }
        } else {
            if (list2.size() > list3.size()) {
                size = list2.size();
            } else {
                size = list3.size();
            }
        }

        for (int i = 0; i < size; i++) {
            if (i < list1.size()) {
                System.out.println(list1.get(i));
            }
            if (i < list2.size()) {
                System.out.println(list2.get(i));
            }
            if (i < list3.size()) {
                System.out.println(list3.get(i));
            }
        }
    }
}

上面的代码给出的输出是：

item1 on list1
item1 on list2
item1 on list3
item2 on list1
item2 on list2
item2 on list3
item3 on list1
item3 on list2
item4 on list2
item5 on list2

如您所见，它交替迭代每个列表