顶部python上具有值的条形图图[复制]

Question

我的熊猫有一张桌子。

    Total_orders    frequency
      0.0           18679137
      1.0           360235
      2.0           68214
      3.0           20512
      4.0           7211
      ...           ...
      50.0          12

我想绘制一个总订单与频率的条形图，频率值显示在每个条形的顶部。

我正在运行这三个代码。代码1：

plt.figure(figsize=(12,6))
df2 = df.groupby('Total_orders')['frequency'].plot(kind='bar')
plt.xlabel('Total_orders')
plt.ylabel('frequency')

for rect in df2.patches:
    height = rect.get_height()
    df2.text(rect.get_x() + rect.get_width()/2., 1.05*height+100,
'%d' % int(height),ha='center', va='bottom', rotation=90)

代码2：（用于循环）

for ii,rect in enumerate(df2.patches):
    height = rect.get_height()
    df2.text(rect.get_x() + rect.get_width()/2., 1.14*height+100,'%d' % int(height),ha='center', va='bottom', rotation=90)

代码3

for p in df2.patches:
df2.annotate(str(p.get_height()), (p.get_x() * 1.005, p.get_height() *1.05),rotation=90)

但是当我运行代码时，它会向我显示错误，那

属性错误：“系列”对象没有属性“补丁”

任何想法为什么会发生这种情况，以及如何删除它？提前致谢。

Answer 1

可能的解决方案如下:

# pip install pandas
# pip install matplotlib

import numpy as np
import matplotlib.pyplot as plt
import pandas as pd

# set test data and create dataframe
data = {'Total_orders': [1,2,3,4,5,6,7,8,9,10], 'frequency': [2,3,4,5,6,7,8,10,11,12]}
df = pd.DataFrame(data)

# set plot fugure size
plt.rcParams["figure.figsize"] = [9,5]

fig, ax = plt.subplots()
rects = ax.bar(df['Total_orders'], df['frequency'], color='r', label='frequency')

ax.set_xlabel('Orders')
ax.set_ylabel('Frequency')
ax.set_title('Frequency per orders')
ax.set_xticks(df['Total_orders'])
ax.legend(loc=2)

# add values on top
ax.bar_label(rects, padding=3)

fig.tight_layout()
plt.show()

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