OpenCV错误：CV：：MAT第522行断言失败

Question

void divideImage(Mat input_image, vector<Mat> output_images, int width_fraction, int height_fraction ) {

int width = input_image.rows / width_fraction - 1;
int height = input_image.cols / height_fraction - 1;

    for (int w = 0; w < input_image.rows; w+=width) {
        for (int h = 0; h < input_image.cols; h+=height) {
            Mat tiles = input_image(Rect(w, h, width, height));
            output_images.push_back(tiles);
        }
    }
}



int main(int argc, char** argv)
{

// Get parameters from command line
CommandLineParser parser(argc, argv, keys);
String image_path1 = parser.get<String>(0);

    if (image_path1.empty())
    {
        help();
        return -1;
    }

// Load image 
cv::Mat img_1_rgb = imread(image_path1, 1);
Mat img_1;
cvtColor(img_1_rgb, img_1, CV_BGR2GRAY);

vector<Mat> output_images(4);

divideImage(img_1, output_images, 2, 2);

 void divideImage(Mat input_image, vector<Mat> output_images, int width_fraction, int height_fraction ) {

 int width = (input_image.cols / width_fraction) - 1;
 int height = (input_image.rows / height_fraction) - 1;

for (int w = 0; w < input_image.cols-width_fraction*width_fraction; w+=width) {
    for (int h = 0; h < input_image.rows-height_fraction*height_fraction; h+=height) {
        Mat tiles = input_image(Rect(w, h, width, height));
        output_images.push_back(tiles);
        //cout << w << " " << h << " " << width << " " << height << " " << endl;
    }
}

Answer 1

你的代码错了。我举个例子：

假设您的图像大小为640x480

现在，让我们使用相同的参数来计算函数的宽度变量

int width = 640 / 2 - 1; // 319

Rect(0, 0, 319, 239)

Rect(319, 0, 319, 239)

Rect(638, 0, 319, 239)

638 + 319 <= 640

您必须改变它的循环方式，在它工作的最佳情况下，您将松散n列/行，即n个划分数。（您可以尝试设置一个限制，如

input_image.rows - width_fraction

在for循环检查中，如果不关心删除的列。

进一步建议，了解如何使用调试器！！它应该跳转到断言，除非您在发布模式下运行它，否则，代码应该总是失败。