图像绘制在错误的位置

Question

这是我的线程的最终输出，它获取屏幕截图并将其存储在一个矢量中。
java.awt.Robot用于获取屏幕截图，这些截图基本上是屏幕的光栅，不包含光标位置。作为一种解决办法，我使用MouseInfo类获取PointerInfo，然后获取一个Point。然后在该点绘制图像。
如果将记录区域设置为全屏分辨率，则一切都很酷。但是，如果我改变了记录区域，光标会被绘制在错误的位置。
这个黑色光标应该在Eclipse IDE的Play按钮的顶部。然而，它处于错误的位置。

package demo;
import java.awt.*;
import java.awt.image.*;
import java.util.*;
import javax.swing.*;

public class ScreenCapturingThread extends Thread{
    public ScreenCapturingThread(Vector<BufferedImage> screenShots,
            int frameRate,
            Icon cursor,
            Rectangle recordingArea){
        this.screenShots = screenShots;
        this.frameRate = frameRate;
        this.cursor = cursor;
        this.recordingArea = recordingArea;

        try{
            bot = new Robot();
        }catch(Exception e){
            System.out.println(e);
        }
        calculateSleepTime();
    }
    @Override
    public void run(){
        while(keepCapturing == true){
            try{
                screenShots.insertElementAt(takeScreenShot(), 0);
                sleep(sleepTime);

                keepCapturing = false; //take only one shot

                System.out.println("here");
                JFrame frame = new JFrame("blah");
                frame.setVisible(true);
                JLabel label = new JLabel(new ImageIcon(screenShots.firstElement()));
                frame.setSize(recordingArea.width, recordingArea.height);
                frame.add(label);


            }catch(InterruptedException e){
                e.printStackTrace();
            }
        }
    }
    public BufferedImage takeScreenShot(){
        p = m.getPointerInfo();
        Point location = p.getLocation();
        image = bot.createScreenCapture(recordingArea);
        if(cursor!=null){
            Graphics g = image.getGraphics();
            g.drawImage(((ImageIcon)cursor).getImage(), location.x,location.y,null);
        }
        return image;
    }
    public void stopIt(){
        keepCapturing = false;
    }
    public void calculateSleepTime(){
        sleepTime = 1/frameRate;
    }

    public static void main(String[] args) {
        Vector<BufferedImage> bufferedImages = new Vector<>(100);
        int frameRate = 10;
        Icon cursor = (Icon) new ImageIcon("src/images/blackCursor.png");
        Rectangle r = new Rectangle(1280,800);
        r.x = 200;
        r.y = 200;
        ScreenCapturingThread sc = new ScreenCapturingThread(bufferedImages,frameRate,cursor,r);

        sc.start();
    }
    Vector<BufferedImage> screenShots;
    int frameRate;
    long sleepTime;
    boolean keepCapturing = true;
    Icon cursor;
    Rectangle recordingArea;
    Robot bot;
    MouseInfo m;
    PointerInfo p;
    BufferedImage image;
}  

如果光标超出记录界限，则不得绘制光标。我是说，你说对了吗？

Answer 1

当然，您必须在相对位置绘制光标--而不是全局位置：

    p = m.getPointerInfo();
    Point location = p.getLocation();

提供鼠标在屏幕上的位置（全局）。鼠标在图像坐标中的位置（相对）如下所示：

    int x = (int) (p.x - recordingArea.getX()); //for int y similar
    if(x < 0 || y < 0 || y >= maxHeight || x >= maxWidth) { // don't draw cursor }