Python3.4 SSL错误urlopen错误EOF违反了协议（_SSL.c:600）

Question

我使用ArchLinux，python 3.4，openSSL 1.0.2d。当我请求https://www.supercash.cz/我得到这个错误。无论我使用请求还是在urllib中构建，总是会有相同的错误。此网站的SSL证书接缝在浏览器Chrome。

File "/usr/lib64/python3.4/urllib/request.py", line 463, in open
    response = self._open(req, data)
File "/usr/lib64/python3.4/urllib/request.py", line 481, in _open
    '_open', req)
File "/usr/lib64/python3.4/urllib/request.py", line 441, in _call_chain
    result = func(*args)
File "/usr/lib64/python3.4/urllib/request.py", line 1225, in https_open
    context=self._context, check_hostname=self._check_hostname)
File "/usr/lib64/python3.4/urllib/request.py", line 1184, in do_open
    raise URLError(err)
urllib.error.URLError: <urlopen error EOF occurred in violation of protocol (_ssl.c:600)>

我试过这个，但它只在python2中有效。7错误-urlopen错误[Errno 8]\u ssl。c:504:EOF违反了协议，需要帮助

这是ssl测试的结果https://www.ssllabs.com/ssltest/analyze.html?d=supercash.cz

Answer 1

这里描述了一种可能的解决方案

https://github.com/kennethreitz/requests/issues/3006#issuecomment-274058323

https://web.archive.org/web/20160705110216/https://github.com/kennethreitz/requests/issues/3006

使用python3并安装组合（pyopenssl-ndg-httpsclient-pyasn1-urllib3）实现了这一点。

pip install pyopenssl ndg-httpsclient pyasn1 urllib3

Answer 2

这与此错误相同：Python请求。例外情况。SSLError:[Errno 8]\u ssl。c:504:EOF违反了协议

您必须使用自定义HTTPAdapter，如下所述：https://stackoverflow.com/a/14146031/407580

>>> import requests
>>> from requests.adapters import HTTPAdapter
>>> from requests.packages.urllib3.poolmanager import PoolManager
>>> import ssl
>>>
>>> class MyAdapter(HTTPAdapter):
...     def init_poolmanager(self, connections, maxsize, block=False):
...         self.poolmanager = PoolManager(num_pools=connections,
...                                        maxsize=maxsize,
...                                        block=block,
...                                        ssl_version=ssl.PROTOCOL_TLSv1)
...
>>> s = requests.Session()
>>> s.mount('https://', MyAdapter())
>>> s.get('https://www.supercash.cz')
<Response [200]>