Java ProcessBuilder和bash

Question

我试图执行一个bash脚本从Java与ProcessBuilder我的代码是：

 Process createUser = buildProcess(
            "/bin/su",
            "-c",
            "\"/opt/somedir/testdir/current/bin/psql",
            "--command",
            commandForUserCreation,
            /* "'select * from users'", */
            "--dbname",
            "mydbname\"",
            "myuser"
            );

问题是我收到错误：

 /bin/su: unrecognized option '--dbname'

如果我将< code>echo放在我的命令的第一个位置，它会在bash中打印正确的命令，如果我复制/粘贴这个命令，它会工作！

请帮我解决这个问题。

Answer 1

这是我在processBuilder中使用的:

String[] command = new String[] {"echo", "Hello"};
String workspace = "/bin/su";
System.out.println("Trying to run command: "+ Arrays.toString(command));
ProcessBuilder probuilder = new ProcessBuilder(command);
probuilder.directory(new File(workspace));

Process process = probuilder.start();
InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
System.out.printf("Output of running %s is:\n",Arrays.toString(command));
while ((line = br.readLine()) != null) {
    System.out.println(line);
}

希望有帮助。

Answer 2

您需要将< code>su要执行的整个命令作为单个参数提供。试试这个:

 Process createUser = buildProcess(
            "/bin/su",
            "-c",
            "/opt/vmware/vpostgres/current/bin/psql --command " + commandForUserCreation + " --dbname mydbname",
            myuser
            );