Python set集合方法
精华
小牛编辑
185浏览
2023-03-14
前面学习了 set 集合，本节来一一学习 set 类型提供的方法。首先，通过 dir(set) 命令可以查看它有哪些方法：
各个方法的具体语法结构及功能如表 1 所示。
>>> dir(set)
['add', 'clear', 'copy', 'difference', 'difference_update', 'discard', 'intersection', 'intersection_update', 'isdisjoint', 'issubset', 'issuperset', 'pop', 'remove', 'symmetric_difference', 'symmetric_difference_update', 'union', 'update']
各个方法的具体语法结构及功能如表 1 所示。
| 方法名 | 语法格式 | 功能 | 实例 |
|---|---|---|---|
| add() | set1.add() | 向 set1 集合中添加数字、字符串、元组或者布尔类型 | >>> set1 = {1,2,3} >>> set1.add((1,2)) >>> set1 {(1, 2), 1, 2, 3} |
| clear() | set1.clear() | 清空 set1 集合中所有元素 | >>> set1 = {1,2,3} >>> set1.clear() >>> set1 set() set()才表示空集合，{}表示的是空字典 |
| copy() | set2 = set1.copy() | 拷贝 set1 集合给 set2 | >>> set1 = {1,2,3} >>> set2 = set1.copy() >>> set1.add(4) >>> set1 {1, 2, 3, 4} >>> set1 {1, 2, 3} |
| difference() | set3 = set1.difference(set2) | 将 set1 中有而 set2 没有的元素给 set3 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set3 = set1.difference(set2) >>> set3 {1, 2} |
| difference_update() | set1.difference_update(set2) | 从 set1 中删除与 set2 相同的元素 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set1.difference_update(set2) >>> set1 {1, 2} |
| discard() | set1.discard(elem) | 删除 set1 中的 elem 元素 | >>> set1 = {1,2,3} >>> set1.discard(2) >>> set1 {1, 3} >>> set1.discard(4) {1, 3} |
| intersection() | set3 = set1.intersection(set2) | 取 set1 和 set2 的交集给 set3 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set3 = set1.intersection(set2) >>> set3 {3} |
| intersection_update() | set1.intersection_update(set2) | 取 set1和 set2 的交集，并更新给 set1 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set1.intersection_update(set2) >>> set1 {3} |
| isdisjoint() | set1.isdisjoint(set2) | 判断 set1 和 set2 是否没有交集，有交集返回 False；没有交集返回 True | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set1.isdisjoint(set2) False |
| issubset() | set1.issubset(set2) | 判断 set1 是否是 set2 的子集 | >>> set1 = {1,2,3} >>> set2 = {1,2} >>> set1.issubset(set2) False |
| issuperset() | set1.issuperset(set2) | 判断 set2 是否是 set1 的子集 | >>> set1 = {1,2,3} >>> set2 = {1,2} >>> set1.issuperset(set2) True |
| pop() | a = set1.pop() | 取 set1 中一个元素，并赋值给 a | >>> set1 = {1,2,3} >>> a = set1.pop() >>> set1 {2,3} >>> a 1 |
| remove() | set1.remove(elem) | 移除 set1 中的 elem 元素 | >>> set1 = {1,2,3} >>> set1.remove(2) >>> set1 {1, 3} >>> set1.remove(4) Traceback (most recent call last): File "<pyshell#90>", line 1, in <module> set1.remove(4) KeyError: 4 |
| symmetric_difference() | set3 = set1.symmetric_difference(set2) | 取 set1 和 set2 中互不相同的元素，给 set3 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set3 = set1.symmetric_difference(set2) >>> set3 {1, 2, 4} |
| symmetric_difference_update() | set1.symmetric_difference_update(set2) | 取 set1 和 set2 中互不相同的元素，并更新给 set1 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set1.symmetric_difference_update(set2) >>> set1 {1, 2, 4} |
| union() | set3 = set1.union(set2) | 取 set1 和 set2 的并集，赋给 set3 | >>> set1 = {1,2,3} >>> set2 = {3,4} >>> set3=set1.union(set2) >>> set3 {1, 2, 3, 4} |
| update() | set1.update(elem) | 添加列表或集合中的元素到 set1 | >>> set1 = {1,2,3} >>> set1.update([3,4]) >>> set1 {1,2,3,4} |