在pyhton词典中搜索

Question

我正在用python和一个我无法解决的字典。我在查字典。我尝试搜索所有medias.items（）中字典words的每个元素，然后四行打印出来，两行用于media[0]，两行用于media[1]。是不是我做错了什么？有办法修好它吗？提前谢谢你。

import requests
import time
from bs4 import BeautifulSoup

headers = {
    'user-agent': "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/84.0.4147.89 Safari/537.36"}


def count_words(url, the_word):
    r = requests.get(url, headers=headers)
    return r.text.lower().count(the_word)

def main():
  #  url = 'https://www.nytimes.com/'
    medias = {
        'Los Angeles Times': ['http://www.latimes.com/'],
        'New York Times': ['http://www.nytimes.com/']
    }

    word = 'trump'
    words = ['Trump', 'Facebook']

    print('--- Iniciando ---')
    print('Hora: ', time.strftime("%X"))
    for web_name, urls in medias.items():
        for url in urls:
            count = count_words(url, words)
            print('La palabra {} aparece {} veces en el sitio del {}.'.format(words, count, web_name))

if __name__ == '__main__':
    main()

Answer 1

我在您的代码中修复了一些错误:

首先，您在使用单词时忘记了循环遍历您的数组，所以我在代码的最后添加了一个for循环来循环遍历那些单词。

其次，在我这样做之后，您的代码返回零，因此我向count_words中的每个单词添加。low（），然后它就工作了。

import requests
import time
from bs4 import BeautifulSoup

headers = {
    'user-agent': "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/84.0.4147.89 Safari/537.36"}


def count_words(url, the_word):
    r = requests.get(url, headers=headers)
    return r.text.lower().count(the_word.lower())

def main():
  #  url = 'https://www.nytimes.com/'
    medias = {
        'Los Angeles Times': ['http://www.latimes.com/'],
        'New York Times': ['http://www.nytimes.com/']
    }

    word = 'trump'
    words = ['Trump', 'Facebook']

    print('--- Iniciando ---')
    print('Hora: ', time.strftime("%X"))
    for web_name, urls in medias.items():
        for url in urls:
            for word in words:
                count = count_words(url, word)
                print('La palabra {} aparece {} veces en el sitio del {}.'.format(word, count, web_name))

if __name__ == '__main__':
    main()

Answer 2

for web_name, urls in medias.items():
        for url in urls:
            for word in words:
                count = count_words(url, word)
                print('La palabra {} aparece {} veces en el sitio del {}.'.format(word, count, web_name))

您传递了一个列表，而应该向count函数传递一个单词。