python - 如何让 pytest 不要屏蔽被测试程序的标准输出?

Question

def test_make_keyword_task(    mock_category_mapping_track_source_ids,    mock_download_rule,    mock_get_uuid):    # Mocking RawRecord    task = RawRecord(        company_id=1,        meta_type="image",        keyword="iphone",        file_path="/image/iphone.jpg",        meta_uuid="iphonx",        is_tracking="started"    )    # Mocking Rules    rules = {1: Rules(category={"some_category": {"nums": 1, "priority": 2}})}    # Calling the function to test    keyword_task_list = make_keyword_task(        task,        "some_url_root",        rules,        push_uuid=None,        category_mapping_track_source_ids=mock_category_mapping_track_source_ids    )        from loguru import logger        logger.debug(keyword_task_list)    print(keyword_task_list)   

不管是最后的 logger.debug 还是 print 都不会显示了，很讨厌！

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python -m pytest common

─➤  python -m pytest common/Users/ponponon/.local/share/virtualenvs/keyword_push-XlDIVWXu/lib/python3.10/site-packages/nameko/testing/pytest.py:101: UserWarning: For versions after 2.13.0, it is recommended to use the `nameko test` cli command. Nameko's pytest plugin no longer applies the eventlet monkeypatch as a pytest hook. This was removed to prevent polluting the environment in case a monkeypatch was not desired. If you need to invoke pytest directly instead of using `nameko test`, you can install the pytest-eventlet plugin, which just performs the automatic monkeypatching that was removed from Nameko. Alternatively you can apply the monkeypatch manually in your conftest.py file.This warning can be suppressed with the --suppress-nameko-eventlet-notification pytest option.  warnings.warn(====================================== test session starts =======================================platform darwin -- Python 3.10.10, pytest-7.4.3, pluggy-1.3.0rootdir: /Users/ponponon/Desktop/code/work/xxxx-it/keyword_pushplugins: nameko-2.14.1, anyio-3.7.1collected 1 item                                                                                 common/test_common.py .                                                                    [100%]======================================== warnings summary ========================================../../../../../.local/share/virtualenvs/keyword_push-XlDIVWXu/lib/python3.10/site-packages/kombu/utils/compat.py:82  /Users/ponponon/.local/share/virtualenvs/keyword_push-XlDIVWXu/lib/python3.10/site-packages/kombu/utils/compat.py:82: DeprecationWarning: SelectableGroups dict interface is deprecated. Use select.    for ep in importlib_metadata.entry_points().get(namespace, [])-- Docs: https://docs.pytest.org/en/stable/how-to/capture-warnings.html================================== 1 passed, 1 warning in 0.16s ==================================(keyword_push) ╭─ponponon@MBP13ARM ~/Desktop/code/work/xxxx-it/keyword_push  ‹feature/v3*› ╰─➤  

Answer 1

pytest 命令加一个 -s 就行

把 python -m pytest common 改成 python -m pytest -s common

Answer 2

你的问题似乎是关于如何在使用 pytest 进行单元测试时，让被测试程序的标准输出不被屏蔽。

在 pytest 中，标准输出（stdout）默认是被捕获的，这样你可以在测试失败时看到更详细的错误信息。然而，这也会导致你的 logger.debug 或 print 的输出无法显示。

解决这个问题的一种方法是使用 -s 或 --capture=no 参数运行 pytest，这样就可以让标准输出不被捕获。

python -m pytest -s common

这样，你的 logger.debug 和 print 的输出就可以正常显示了。

注意：这会让你的测试输出变得不可控，你可能无法看到失败的详细信息。因此，建议只在调试时使用这种方法。在生产环境中，还是应该使用默认的 stdout 捕获模式。