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javascript - 两个数组对象去重并且根据第一个数据生成一个新的对象?

马俊
2023-09-04

各位大佬,我想请问一下我想通过一个数组对象处理另外一个数组对象。生成一个新的数组对象要怎么处理?我想通过两个时间的字段做判断,给新生成的数组对象里面属性的值加上一个1。怎么写都不对。生成的都是有问题的。

通过的数组对象

thisDate: [{            date: "12",            prop: "twelve"        },{            date: "13",            prop: "thirteen"        },{            date: "14",            prop: "fourteen"        },{            date: "15",            prop: "fifteen"        },{            date: "16",            prop: "sixteen"        },{            date: "17",            prop: "seventeen"        },{            date: "18",            prop: "eighteen"        }],

想要处理的数组对象

data: [{            "DATE": "2023-09-04 15:33:54.0",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 16:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 17:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 18:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 19:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 20:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 21:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 22:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 23:00:00",            "ROOMNAME": "测试会议室1",            "ROOMID": "001"        }, {            "DATE": "2023-09-04 14:53:42.0",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }, {            "DATE": "2023-09-04 15:00:00",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }, {            "DATE": "2023-09-04 16:00:00",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }, {            "DATE": "2023-09-04 17:00:00",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }, {            "DATE": "2023-09-04 18:00:00",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }, {            "DATE": "2023-09-04 19:00:00",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }, {            "DATE": "2023-09-04 20:00:00",            "ROOMNAME": "会议室2222",            "ROOMID": "002"        }]

我的思路有问题想不出来了,写的代码不对生成的有问题。

let list = [];                    for (let i = 0; i < data.length; i++) {                        let nextIndex = i + 1                        let nextEle = data[nextIndex]                        if (nextIndex < data.length) {                            if (data[i].ROOMNAME != nextEle.ROOMNAME) {                                let objData = {                                    name: nextEle.ROOMNAME,                                }                                for (let a = 0; a < _this.thisDate.length; a++) {                                    if (data[i].DATE.slice(11, 13) == _this.thisDate[a].date) {                                        objData[_this.thisDate[a].prop] = '1';                                    } else {                                        objData[_this.thisDate[a].prop] = '';                                    }                                }                                list.push(objData)                            }                        }                    }                    console.log('生成新的数组对象');                    console.log(list);

我希望的是生成新的数组对象,合并同名,并且根据thisDate生成新的属性。在和data这个json判断时间对等的属性赋值1。

最后希望生成的格式格式是:

[{            ROOMNAME: '测试会议室',            twelve: '',            thirteen: '',            fourteen: '',            fifteen: '',            sixteen: '1',            seventeen: '1',            eighteen:'1',        },{            ROOMNAME: '会议室2222',            twelve: '',            thirteen: '',            fourteen: '1',            fifteen: '1',            sixteen: '1',            seventeen: '1',            eighteen:'1',        }]

共有1个答案

郗唯
2023-09-04

如果没有看错的话,就是记录一下各会议室在某个小时段是否有开会。说一下解法。

前两个数据是一样的:

const thisDate = [  {    date: "12",    prop: "twelve",  },  {    date: "13",    prop: "thirteen",  },  {    date: "14",    prop: "fourteen",  },  {    date: "15",    prop: "fifteen",  },  {    date: "16",    prop: "sixteen",  },  {    date: "17",    prop: "seventeen",  },  {    date: "18",    prop: "eighteen",  },];
const data = [  {    DATE: "2023-09-04 15:33:54.0",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 16:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 17:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 18:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 19:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 20:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 21:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 22:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 23:00:00",    ROOMNAME: "测试会议室1",    ROOMID: "001",  },  {    DATE: "2023-09-04 14:53:42.0",    ROOMNAME: "会议室2222",    ROOMID: "002",  },  {    DATE: "2023-09-04 15:00:00",    ROOMNAME: "会议室2222",    ROOMID: "002",  },  {    DATE: "2023-09-04 16:00:00",    ROOMNAME: "会议室2222",    ROOMID: "002",  },  {    DATE: "2023-09-04 17:00:00",    ROOMNAME: "会议室2222",    ROOMID: "002",  },  {    DATE: "2023-09-04 18:00:00",    ROOMNAME: "会议室2222",    ROOMID: "002",  },  {    DATE: "2023-09-04 19:00:00",    ROOMNAME: "会议室2222",    ROOMID: "002",  },  {    DATE: "2023-09-04 20:00:00",    ROOMNAME: "会议室2222",    ROOMID: "002",  },];

使用哈希表做一个前置处理,根据会议室名称进行分组,其值为该会议室开会的小时。

注意,此处比较随意。若是严谨一点,应当使用 ROOMID 作为 keyvalue 也应当使用 Set 作为容器,以免数据量大导致的重复问题。
const map = new Map();for (const { DATE, ROOMNAME } of data) {  map.set(ROOMNAME, [...(map.get(ROOMNAME) ?? []), DATE.slice(11, 13)]);}

最后遍历哈希表,与 thisDate 对照一下,即可得到结果:

const list = [];for (const [k, v] of map.entries()) {  const obj = {    name: k,  };  for (const { prop, date } of thisDate) {    obj[prop] = v.includes(date) ? "1" : "";  }  list.push(obj);}console.log("生成新的数组对象");console.log(list);

结果如下:

生成新的数组对象[  {    name: '测试会议室1',    twelve: '',    thirteen: '',    fourteen: '',    fifteen: '1',    sixteen: '1',    seventeen: '1',    eighteen: '1'  },  {    name: '会议室2222',    twelve: '',    thirteen: '',    fourteen: '1',    fifteen: '1',    sixteen: '1',    seventeen: '1',    eighteen: '1'  }]
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