Libgdx切换屏幕

Question

在libGDX中切换屏幕似乎有问题。它会切换到游戏屏幕，但不会切换回主屏幕，也不会切换到屏幕上的游戏。我的游戏课：

@Override
public void create() {
    menu();
}

public void play(){
    this.setScreen(new GameSc(this));
    play = true;
}
public void menu(){


    this.setScreen(new GameMenu(this));
    menu = true;
}
public void gameOver(){

    this.setScreen(new GameOver(this));

}

我的GameScreen类（实现屏幕）：

public GameSc(GameRunner runner) {
    this.runner = runner;

    background = new Texture(Gdx.files.internal("Textures/background.png"));
    batch = new SpriteBatch();




    box = new Box(this);

    txt = new Texture(Gdx.files.internal("Textures/Enemies/Boxers/Enemy.png"));

    snakes = new ArrayList<Snake>();
    enemies = new ArrayList<Enemy>();

    shape = new ShapeRenderer();

    Gdx.gl.glClearColor(1f, 1f, 1f, 1f);

    new Thread(new Runnable() {

        @Override
        public void run() {
            while(true){
                update();
            }

        }
    }).start();

    snakeThread();
    enemyThread();
}

@Override
public void show() {


    //initialize

}



@Override
public void resize(int width, int height) {



}



@Override

public void render(float dt) {

    Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
    //Drawing an image.
    batch.begin();
    batch.draw(background, 0,0 , Gdx.graphics.getWidth(), Gdx.graphics.getHeight());
    batch.end();
    box.render(batch);
            for (int i = 0; i < snakes.size(); i++) {

                snakes.get(i).render(shape);
            }

    for (int i = 0; i < enemies.size(); i++) {
        enemies.get(i).render(batch);
    }

}
public void update(){

    box.update();
    for (int i = 0; i < snakes.size(); i++) {
        snakes.get(i).update();
    }

    for (int i = 0; i < snakes.size(); i++) {

        if(!(snakes.get(i).isAlive)){
            snakes.remove(i);
            System.out.println(snakes.size());
        }


    }

}

private void snakeThread(){
    new Thread(new Runnable() {
    Random r = new Random();
    //float[]anglem = {30,40,50,60,70,80,90,100};   

    @Override
    public void run() {
        while(true){
            int x = r.nextInt(Gdx.graphics.getWidth()-50);
            int y = r.nextInt(Gdx.graphics.getHeight()-50);
            int delay = r.nextInt((6000-2000)+1)+2000;
            int speed = MathUtils.random(50, 150);
            float angle = (float) r.nextInt((110-30)+1)+30;
            int length = MathUtils.random(15, 25);
            try {
                spawnSnake(x, y, angle, length, speed);
                //System.out.println(delay);
                Thread.sleep(delay);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

        }

    }
}).start();

    box.update();
}

private void enemyThread(){
    new Thread(new Runnable() {

        @Override
        public void run() {
            while(true){
                int x = MathUtils.random(Enemy.UNIFORM_WIDTH, Gdx.graphics.getWidth()-Enemy.UNIFORM_WIDTH);
                int y = 0;
                int speed = 15;
                int delay = MathUtils.random(400, 600);


                try {
                    spawnEnemy(x, y, speed, txt);
                        for (int i = 0; i < enemies.size(); i++) {
                            if(enemies.get(i).getY()<0){
                                enemies.remove(i);
                            }

                        }

                    Thread.sleep(delay);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }

            }

        }
    }).start();

    box.update();
}


public void spawnSnake(int x, int y, float angle, int length, int speed){
    Snake snake = new Snake(angle,new Vector2(x,y),speed,length);
    snakes.add(snake);

}

public void spawnEnemy(int x, int y, int speed, Texture currentTexture){
    Enemy enemy = new Enemy(x , y , speed, Enemy.UNIFORM_WIDTH, Enemy.UNIFORM_HEIGHT, txt);
    enemies.add(enemy);

}



@Override
public void pause() {


}

@Override
public void resume() {


}

@Override
public void dispose() {
    if(runner.menu==false){
        runner.getScreen().dispose();
        shape.dispose();
        batch.dispose();
        }


}



@Override
public void hide() {
    // TODO Auto-generated method stub

}

这就是我如何更改屏幕（不工作）：

if (bounds.contains(g.snakes.get(i).snake.get(y).x, g.snakes.get(i).snake.get(y).y) && isAlreadyTouched) {
                    isAlreadyTouched = false;
                    g.runner.play=false;
                    g.runner.gameOver();
                    }

你可以在这里找到全部来源。

Answer 1

有很多方法可以解决一个问题，我不想通读你发布的源代码，但是你发布的一行肯定不会改变屏幕。

if (bounds.contains(g.snakes.get(i).snake.get(y).x, g.snakes.get(i).snake.get(y).y) && isAlreadyTouched) {
                    isAlreadyTouched = false;
                    g.runner.play=false;
                    g.runner.gameOver();
                    }

我不确定源代码的体系结构，可能存在由g.runner触发的侦听器事件。gameOver（） 或g.runner。play=false`然后下面的解决方案最终会给你带来麻烦。

if (bounds.contains(g.snakes.get(i).snake.get(y).x, g.snakes.get(i).snake.get(y).y) && isAlreadyTouched) {
                    isAlreadyTouched = false;
                    g.runner.play=false;
                    g.runner.gameOver();
                    //Now set a screen
                    ((Game)Gdx.app.getApplicationListener).setScreen(new GameOver(this);
                }

我个人喜欢像上面那样使用屏幕。每当我需要更改屏幕时，我将应用程序监听器转换为游戏程序，这样我就可以设置新的（或推送现有的）屏幕。

但正如我所说，您可能已经删除或尚未实现应该调用游戏类中的方法来更改屏幕的代码。

Answer 2

通过将g.runner.set屏幕（新的游戏结束（this））移动到另一个线程来解决这个问题。