如何从数组中的所有对象中删除一个简单的特定键值对[重复]

Question

我正在学习ES6和对象，想知道如何在这个对象数组中去掉一个键值对：

[
    { "name" : "mark", "height" : "tall", "theId" : "1", "nat" : "uk"},
    { "name" : "ben", "height" : "medium", "theId" : "2", "nat" : "uk"},
    { "name" : "neil", "height" : "small", "theId" : "3", "nat" : "uk" }
]

结果应该是：

[
    { "name" : "mark", "height" : "tall", "nat" : "uk"},
    { "name" : "ben", "height" : "medium", "nat" : "uk"},
    { "name" : "neil", "height" : "small", "nat" : "uk" }
]

我创建了一个foreach函数，并试图将每个结果推入一个新的数组，但现在没有对象。

这怎么能解决呢？或者有更好的方法来使用ES6/ES7语法？感谢任何帮助。代码和codePen URL如下：

代码笔：https://codepen.io/anon/pen/bPYQyb

let objArr = [
	{ "name" : "mark", "height" : "tall", "theId" : "1", "nat" : "uk"},
	{ "name" : "ben", "height" : "medium", "theId" : "2", "nat" : "uk"},
	{ "name" : "neil", "height" : "small", "theId" : "3", "nat" : "uk" }
],
    arr = [];

objArr.forEach(function(obj) {
	for (let column in obj) {
      let currArr = [];
    if (isNaN(obj[column])) {
      console.log('true');
      currArr.push(obj[column]);
    }
    arr.push(currArr);
  }
});

console.log(arr);

Answer 1

如果要在位修改当前对象，可以在数组中循环对象并使用delete

所以你可以

for (let obj of objArr) {
  delete obj.theId;
}

或者功能方式

objArr.forEach(obj => delete obj.theId);

Answer 2

只需删除密钥：

let objArr = [
	{ "name" : "mark", "height" : "tall", "theId" : "1", "nat" : "uk"},
	{ "name" : "ben", "height" : "medium", "theId" : "2", "nat" : "uk"},
	{ "name" : "neil", "height" : "small", "theId" : "3", "nat" : "uk" }
];


objArr.forEach(function(obj) {
	delete obj.theId;
});

console.log(objArr);

Answer 3

objArr.forEach(a => delete a.theId);

删除操作员的单据：https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/delete