从另一个数组中存在的对象数组中删除对象[重复]

Question

let existing_array  = [
    {name: "a",  age: 15},
    {name: "b",  age: 16},
    {name: "c",  age: 17},
    {name: "d",  age: 18}
    {name: "e",  age: 19}];

现在我有了新阵列

let new_array =  = [
    {name: "f",  age: 15},
    {name: "b",  age: 16},
    {name: "g",  age: 17},
    {name: "h",  age: 18}
    {name: "i",  age: 19}];

现在，现有的_array和新的_array都有名称值“b”，我希望它从新数组中移除

Answer 1

使用filter（）与search组合使用：

new_array = new_array.filter(x => !existing_array.find(y => x.age === y.age && x.name === y.age))

您可能需要使用更好的平等检查。