ORA-00001：违反了唯一约束主键

Question

DELETE from dbo.T_LIAV_AGENT_STATE_APPROVAL SAP
WHERE EXISTS (SELECT UNIQUE 1 FROM MCS_SYNC_STATE_APPR APP

                inner join MCS_SYNC_NAME SN on SN.SE_NAME_ID = APP.SE_NAME_ID
                                    and SN.ACTION in('U','S')
                Where APP.SE_name_id = SAP.AV_NAME_ID
                and APP.SYNC_INSTANCE_ID = param_inst_ID);
COMMIT;

INSERT INTO dbo.T_LIAV_AGENT_STATE_APPROVAL

SELECT  UNIQUE 

    APP.SE_NAME_ID            AS AV_NAME_ID,
    APP.STATE                 AS AV_STATE,
    APP.APPROVAL_TYPE         AS AV_APPROVAL_TYPE,
    APP.START_DATE            AS AV_START_DATE,
    APP.END_DATE              AS AV_END_DATE,
    APP.APPOINTED             AS AV_APPOINTED,
    APP.RENEWAL_DATE          AS AV_RENEWAL_DATE,
    APP.LICENSE               AS AV_LICENSE,
    COMPANY_NAME_ID           as AV_COMPANY_CODE,
    SYSDATE                   AS TSTAMP,
    SYNC_USER_NAME_ID         AS AV_FIRST_USER_ID,
    SYSDATE                   AS AV_FIRST_DATE,
    NULL                      AS AV_LAST_USER_ID,
    NULL                      AS AV_LAST_DATE

FROM MCS_SYNC_STATE_APPR APP

WHERE exists (select 1 from t_liag_agent AG
                     where AG.ag_name_id = APP.SE_NAME_ID)
and APP.SYNC_INSTANCE_ID = param_inst_ID;

以下是SQL部分，我在调试代码时出错：

ORA-00001：唯一约束主键违反T_LIAV_AGENT_STATE_APPROVAL...

这是主键约束依赖的2列AV_NAME_ID，AV_STATE...

我没有重复的数据...你认为还有其他原因吗？

Answer 1

如果不确定违反了哪个唯一约束，可以运行以下SQL：

Select Distinct table_name
From all_indexes
Where index_name = 'CONSTRAINT_NAME';

Answer 2

与Insert table语句相比，Select语句缺少一列，因此出现此错误。当我将该列添加到select语句时，它工作得非常好。

Answer 3

如果您有“创建表”权限，请使用dbms\u errlog包。

>

begin
  dbms_errlog.create_error_log('DBO.T_LIAV_AGENT_STATE_APPROVAL');
end;
/

使用附加子句运行您的INSERT脚本：

INSERT INTO dbo.T_LIAV_AGENT_STATE_APPROVAL
SELECT ...
FROM ...
LOG ERRORS INTO err$_T_LIAV_AGENT_STATE_APPROVAL REJECT LIMIT UNLIMITED;

检查错误记录表中的错误：

select * from err$_T_LIAV_AGENT_STATE_APPROVAL;

您将看到所有违反约束的记录和错误消息。