如何在一定时间后停止输入（）函数？

Question

我试图找出如何使python停止接受输入后一定数量的时间。

到目前为止，我已经得到了工作，但不会停止程序，直到用户按下回车键。如果有关系，我在蟒蛇提示符中运行这个文件。

#I've made everything short so it's simpler
def f():
    try:
        if a != "Accepted word":
            timer.cancel
            print("...")
            quit()

    except NameError:
            #This makes the code run anyway since if the user inputs nothing 
            #'a' will still be undefined and python will still be waiting for an input
            timer.cancel
            print("...")
            if a == "":
            quit()
            #Like I said, Python won't actually stop until an input is made
    else:
        #This runs fine if the user inputs the 'accepted word'
        timer.cancel
        print(...)
        quit()
timer = threading.Timer(5.0, f)
timer.start()
a = input(">")

换句话说，我想做一些东西，这样Python就不会再等待输入了。如果用户在计时器结束前输入了任何东西，程序运行正常，这很好，除非玩家什么也没输入。如果他们甚至不按回车键，那么整个过程就会停止。（我也是Python的绝对初学者。事实上，仅仅学习如何制作计时器和使用time.sleep功能就花了我几个小时）（顺便说一句，这也是我的知识范围）

Answer 1

只需使用time.sleep（）Hibernate方法会使python程序冻结一定时间（以毫秒为单位）。所以，如果你想停止输入（）一段时间，那么你可以这样做，

from time import sleep
sleep(1000) #stops the program for 1 seconds
s = input()

调味汁

Answer 2

您可以为此使用多线程。

from threading import Thread
import time
import os

answer = None


def ask():
    global start_time, answer
    start_time = time.time()
    answer = input("Enter a number:\n")
    time.sleep(0.001)


def timing():
    time_limit = 5
    while True:
        time_taken = time.time() - start_time
        if answer is not None:
            print(f"You took {time_taken} seconds to enter a number.")
            os._exit(1)
        if time_taken > time_limit:
            print("Time's up !!! \n"
                  f"You took {time_taken} seconds.")
            os._exit(1)
        time.sleep(0.001)


t1 = Thread(target=ask)
t2 = Thread(target=timing)
t1.start()
t2.start()