我有以下实体:
@Entity
public class CityExpert {
@Id
private long id;
@OneToOne
private User user;
@OneToMany(mappedBy = "cityExpert")
private List<CityExpertDocument> documents;
// Lots of other fields...
}
@Entity
public class CityExpertDocument {
@Id
private long id;
@ManyToOne
private CityExpert cityExpert;
// Lots of other fields...
}
@Entity
public class User {
@Id
private long id;
private String name;
private String email;
// Lots of other fields...
}
我有以下HQL查询,其中我选择了CityExpert的子集:
"select " +
"e " +
"from " +
"CityExpert e " +
"where " +
"( (lower(e.user.name) like concat('%', lower(?1), '%') or e.user.name is null) or ?1 = '' ) " +
"and " +
"( (lower(e.user.phone) like concat('%', lower(?2), '%') or e.user.phone is null) or ?2 = '' ) "
但是,由于CityExpert中的字段太多,我不想选择所有字段。因此,我将查询更改如下:
"select " +
"e.user.name, " +
"e.user.email, " +
"e.documents " +
"from " +
"CityExpert e " +
"where " +
"( (lower(e.user.name) like concat('%', lower(?1), '%') or e.user.name is null) or ?1 = '' ) " +
"and " +
"( (lower(e.user.phone) like concat('%', lower(?2), '%') or e.user.phone is null) or ?2 = '' ) "
然而,显然,我们无法在这样的实体中选择一对多字段,因为我在前面的查询中得到了一个MySQLSyntaxErrorException(参考这个问题)。因此,我将查询更改为:
"select " +
"e.user.name, " +
"e.user.email, " +
"d " +
"from " +
"CityExpert e " +
"left join " +
"e.documents d" +
"where " +
"( (lower(e.user.name) like concat('%', lower(?1), '%') or e.user.name is null) or ?1 = '' ) " +
"and " +
"( (lower(e.user.phone) like concat('%', lower(?2), '%') or e.user.phone is null) or ?2 = '' ) "
但是,这次结果变成了List
我已创建以下DTO:
public class CityExpertDTO {
private String name;
private String email;
private List<CityExpertDocument> documents;
}
但是,我不知道应该如何将Hibernate返回的结果映射到
List
我正在使用Spring Data JPA并使用HQL,如下所示:
public interface CityExpertRepository extends JpaRepository<CityExpert, Long> {
@Query(
"select " +
"e " +
"from " +
"CityExpert e " +
"where " +
"( (lower(e.user.name) like concat('%', lower(?1), '%') or e.user.name is null) or ?1 = '' ) " +
"and " +
"( (lower(e.user.phone) like concat('%', lower(?2), '%') or e.user.phone is null) or ?2 = '' ) "
)
Set<CityExpert> findUsingNameAndPhoneNumber(String name,
String phoneNumber);
}
如何将结果映射到CityExpertDTO?
假设我们有以下post
和post_comment
表,它们通过post_comment
表中的post_id
外键列形成一对多关系。
考虑到我们有一个用例,只需要从post
表中获取id和title列,以及从post\u comment
表中获取id和review列,我们可以使用以下JPQL查询来获取所需的投影:
select p.id as p_id,
p.title as p_title,
pc.id as pc_id,
pc.review as pc_review
from PostComment pc
join pc.post p
order by pc.id
运行上面的投影查询时,我们得到以下结果:
| p.id | p.title | pc.id | pc.review |
|------|-----------------------------------|-------|---------------------------------------|
| 1 | High-Performance Java Persistence | 1 | Best book on JPA and Hibernate! |
| 1 | High-Performance Java Persistence | 2 | A must-read for every Java developer! |
| 2 | Hypersistence Optimizer | 3 | It's like pair programming with Vlad! |
但是,我们不想使用基于表格的结果集或默认列表
我们可以使用Hibernate ResultTransformer,如下例所示:
List<PostDTO> postDTOs = entityManager.createQuery("""
select p.id as p_id,
p.title as p_title,
pc.id as pc_id,
pc.review as pc_review
from PostComment pc
join pc.post p
order by pc.id
""")
.unwrap(org.hibernate.query.Query.class)
.setResultTransformer(new PostDTOResultTransformer())
.getResultList();
assertEquals(2, postDTOs.size());
assertEquals(2, postDTOs.get(0).getComments().size());
assertEquals(1, postDTOs.get(1).getComments().size());
PostDTOResultTransformer将定义对象[]投影与包含子DTO对象的PostDTO对象之间的映射:
public class PostDTOResultTransformer
implements ResultTransformer {
private Map<Long, PostDTO> postDTOMap = new LinkedHashMap<>();
@Override
public Object transformTuple(
Object[] tuple,
String[] aliases) {
Map<String, Integer> aliasToIndexMap = aliasToIndexMap(aliases);
Long postId = longValue(tuple[aliasToIndexMap.get(PostDTO.ID_ALIAS)]);
PostDTO postDTO = postDTOMap.computeIfAbsent(
postId,
id -> new PostDTO(tuple, aliasToIndexMap)
);
postDTO.getComments().add(
new PostCommentDTO(tuple, aliasToIndexMap)
);
return postDTO;
}
@Override
public List transformList(List collection) {
return new ArrayList<>(postDTOMap.values());
}
}
aliasToIndexMap
只是一个小实用程序,它允许我们构建一个Map
结构,该结构将列别名和列值位于Object[]
tuple
数组中的索引相关联:
public Map<String, Integer> aliasToIndexMap(
String[] aliases) {
Map<String, Integer> aliasToIndexMap = new LinkedHashMap<>();
for (int i = 0; i < aliases.length; i++) {
aliasToIndexMap.put(aliases[i], i);
}
return aliasToIndexMap;
}
我们将在postDTOMap中存储所有实体,这些实体最终将由查询执行返回。我们使用postDTOMap的原因是,每个子记录的SQL查询结果集中的父行都是重复的。
只有在postDTOMap中没有存储现有的PostDTO引用时,computeIfAbsent方法才允许我们创建PostDTO对象。
PostDTO
类有一个构造函数,可以使用专用列别名设置id
和title
属性:
public class PostDTO {
public static final String ID_ALIAS = "p_id";
public static final String TITLE_ALIAS = "p_title";
private Long id;
private String title;
private List<PostCommentDTO> comments = new ArrayList<>();
public PostDTO(
Object[] tuples,
Map<String, Integer> aliasToIndexMap) {
this.id = longValue(tuples[aliasToIndexMap.get(ID_ALIAS)]);
this.title = stringValue(tuples[aliasToIndexMap.get(TITLE_ALIAS)]);
}
//Getters and setters omitted for brevity
}
PostCommentDTO
以类似的方式构建:
public class PostCommentDTO {
public static final String ID_ALIAS = "pc_id";
public static final String REVIEW_ALIAS = "pc_review";
private Long id;
private String review;
public PostCommentDTO(
Object[] tuples,
Map<String, Integer> aliasToIndexMap) {
this.id = longValue(tuples[aliasToIndexMap.get(ID_ALIAS)]);
this.review = stringValue(tuples[aliasToIndexMap.get(REVIEW_ALIAS)]);
}
//Getters and setters omitted for brevity
}
那就是了!
使用PostDTOResultTransformer,可以将SQL结果集转换为分层DTO投影,这非常方便使用,尤其是当需要将其编组为JSON响应时:
postDTOs = {ArrayList}, size = 2
0 = {PostDTO}
id = 1L
title = "High-Performance Java Persistence"
comments = {ArrayList}, size = 2
0 = {PostCommentDTO}
id = 1L
review = "Best book on JPA and Hibernate!"
1 = {PostCommentDTO}
id = 2L
review = "A must read for every Java developer!"
1 = {PostDTO}
id = 2L
title = "Hypersistence Optimizer"
comments = {ArrayList}, size = 1
0 = {PostCommentDTO}
id = 3L
review = "It's like pair programming with Vlad!"
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