查找并环绕DIV中的所有选定单词

Question

我有一些预定义的单词，我想在句子中找到这些单词，并添加一个SPAN标签。

例如

Lorem Ipsum只是印刷和排版行业的虚拟文本。自16世纪以来，Lorem Ipsum一直是行业标准的虚拟文本，当时一位不知名的印刷商拿起一个打印工具，将其拼凑成一本打印样本书。

在这句话中，我想在单词中添加一个SPAM标签：

话：

• 行业标准

DOM将是这样的

<div class="exampleArticle">
    Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has 
    been the <span id="marked">industry's standard</span> dummy text ever since the <span id="marked">1500s</span>, when an unknown 
    printer took a galley of type and scrambled it to make a type <span id="marked">specimen book</span>.
</div>

代码：

$in = 'Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry\'s standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.';

    $words = array(
        "industry's standard", "1500s", "specimen book"
    ); 
    $wrap_before = '<span id="marked">';
    $wrap_after  = '</span>';

    $out = preg_replace("/($words)/i", "$wrap_before$1$wrap_after", $in);

Answer 1

您需要将正则表达式模式（包括捕获组）放在数组的每个项中。按照现在的方式，您正在尝试将数组注入字符串，这可能会产生“数组到字符串转换”错误。

$input = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.";

$replaceText = array("/(industry's standard)/", "/(1500s)/", "/(specimen book)/");
$wrapBefore = '<span id="marked">';
$wrapAfter = '</span>';

$output = preg_replace($replaceText, "$wrapBefore$1$wrapAfter", $input);

echo $output;

我不能100%确定这是否是实现这一点的最有效方法，但它确实得到了您想要的（您可以添加外部

演示

或者，这里有一个使用str\u replace（）和array\u walk（）的版本（这个想法归功于Alex）

$input = "Lorem Ipsum has been the industry\'s standard dummy text ever since the 1500s.. to make a type specimen book.";

$searchArray = array("industry's standard", "1500s", "specimen book");
$replacementArray = $searchArray;

$wrapBefore = '<span id="marked">';
$wrapAfter = '</span>';
array_walk($replacementArray, "addWrappers", array($wrapBefore, $wrapAfter));

$output = str_replace($searchArray, $replacementArray, stripslashes($input));

echo $output;

function addWrappers(&$searchTerm, $key, $additionalText)
{
    $searchTerm = $additionalText[0] . $searchTerm . $additionalText[1];
}

演示

Answer 2

当你不需要使用正则表达式时，千万不要使用正则表达式str_replace（）非常适合您。有很多方法可以得到你想要的东西。最明显的是每次替换只需调用一次str_replace（），不断更新相同的输出字符串：

$out = $in;
foreach ($words as $word) {
    $out = str_replace($word, '<pre>' . $word . '<post>', $out);
}

如果您想获得更多乐趣，可以利用str_replace（）array功能，一次完成所有操作：

$out = str_replace(
    $words,
    array_map(function($word){ return '<pre>' . $word . '<post>'; }, $words),
    $in
);