根据我的序列对hashmap进行排序

Question

String sequence="People,Object,Environment,Message,Service";
HashMap<String, String> lhm = new HashMap<String, String>();
List<String> list=new ArrayList<String>();
lhm.put("Objectabc", "biu");
lhm.put("Message someText", "nuios");
lhm.put("Servicexyxyx", "sdfe");
lhm.put("People bcda", "dfdfh");
lhm.put("Environment qwer", "qwe");
lhm.put("Other", "names");
lhm.put("Elements", "ioup");            
lhm.put("Rand", "uiy");

// Get a set of the entries
Set<Entry<String, String>> set = lhm.entrySet();
String[] resultSequence=sequence.split(",");

for(int j=0;j<resultSequence.length;j++)
{
    Iterator<Entry<String, String>> iter = set.iterator();
    while(iter.hasNext()) {

       Map.Entry me = (Map.Entry)iter.next();
       String res=(String) me.getKey();

       if(res.contains(resultSequence[j]))
       {
           System.out.println("values according with the sequence is "+res);
       }
       if(!res.contains(resultSequence[j]))
       {
           list.add(res);
           // System.out.println("values not according with the sequence is "+res);
       }

    }  

 }

 List<String> list2=new ArrayList<String>(new LinkedHashSet<String>(list));

 Iterator<String> iterlist2=list2.iterator();
 while(iterlist2.hasNext())
 {
     System.out.println("non equal elements are "+iterlist2.next());
 }

values according with the sequence is People bcda
values according with the sequence is Objectabc
values according with the sequence is Environment qwer
values according with the sequence is Message someText
values according with the sequence is Servicexyxyx
non equal elements are Elements
non equal elements are Other
non equal elements are Servicexyxyx
non equal elements are Objectabc
non equal elements are Message someText
non equal elements are Rand
non equal elements are Environment qwer
non equal elements are People bcda

values according with the sequence is People bcda
values according with the sequence is Objectabc
values according with the sequence is Environment qwer
values according with the sequence is Message someText
values according with the sequence is Servicexyxyx
non equal elements are Elements
non equal elements are Other
non equal elements are Rand

编辑：对于同样的问题，我尝试编写一个比较器。但它不起作用

Comparator<String> comparator = new Comparator<String>() {
             @Override
             public int compare(String key1, String key2) {
                 int returned = sequence.indexOf(key1) - sequence.indexOf(key2);

                 if (returned == 0 && !key1.contains(key2))
                     returned = -1;

                 return returned;

             }
         }; 

Answer 1

您的问题似乎是，您正在迭代序列，对于序列中的每个元素，您都在迭代映射并添加每个不匹配的元素。

我猜你想要这样的东西：

• 创建映射的副本
• 用于序列中的每个元素
  • 用于映射副本中的每个条目（此处使用迭代器，因为您必须对其调用remove())
    • 如果条目与sequenc元素匹配
      • 添加到列表
      • 从映射副本中删除当前条目（这就是您需要该副本的原因）

      String sequence = "People,Object,Environment,Message,Service";
      
      Map<String, String> lhm = new TreeMap<String, String>();
      lhm.put( "Objectabc", "biu" );
      lhm.put( "Message someText", "nuios" );
      lhm.put( "Servicexyxyx", "sdfe" );
      lhm.put( "People bcda", "dfdfh" );
      lhm.put( "Environment qwer", "qwe" );
      lhm.put( "Other", "names" );
      lhm.put( "Elements", "ioup" );
      lhm.put( "Rand", "uiy" );
      
      for( String element : sequence.split( "," ) )
      {
        final String elem = element;
      
        //try to get the value and remove it in one step
        String value = lhm.remove( new Comparable<String>()
        {
          public int compareTo( String other )
          {
            if( other.contains( elem ) )
            {
              return 0;
            }
      
            return elem.compareTo( other );
          }
        } );
      
        if( value != null )
        {
          System.out.println("values according with the sequence (key:" + element + ") is " + value); 
        }
      }
      
      for( Map.Entry<String, String> e : lhm.entrySet())
      {
        System.out.println("non equal elements are " + e.getKey() + " (value: " + e.getValue() + ")");
      }
      

      values according with the sequence (key:People) is dfdfh
      values according with the sequence (key:Object) is biu
      values according with the sequence (key:Environment) is qwe
      values according with the sequence (key:Message) is nuios
      values according with the sequence (key:Service) is sdfe
      non equal elements are Elements (value: ioup)
      non equal elements are Other (value: names)
      non equal elements are Rand (value: uiy)