根据特定值对ArrayList进行排序

Question

我有一个数组列表 假设[“monday”,“mesday”,“friday”]

我的目的是以循环的方式基于DayoftheWeek来订购它。

输入:“星期三”

SortedList:[“星期三”,“星期五”,“星期一”]

Answer 1

演示：

import java.time.DayOfWeek;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        List<DayOfWeek> list = new ArrayList<>(List.of(DayOfWeek.MONDAY, DayOfWeek.TUESDAY, DayOfWeek.WEDNESDAY,
                DayOfWeek.THURSDAY, DayOfWeek.FRIDAY, DayOfWeek.SUNDAY));

        Collections.rotate(list, list.size() - list.indexOf(DayOfWeek.WEDNESDAY));

        System.out.println(list);
    }
}

输出：

[WEDNESDAY, THURSDAY, FRIDAY, SUNDAY, MONDAY, TUESDAY]

交互式：

import java.time.DayOfWeek;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        List<DayOfWeek> list = new ArrayList<>(List.of(DayOfWeek.MONDAY, DayOfWeek.TUESDAY, DayOfWeek.WEDNESDAY,
                DayOfWeek.THURSDAY, DayOfWeek.FRIDAY, DayOfWeek.SUNDAY));

        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter the day: ");
        String day = scanner.nextLine();

        try {
            Collections.rotate(list, list.size() - list.indexOf(DayOfWeek.valueOf(day.toUpperCase())));
            System.out.println(list);
        } catch (IllegalArgumentException e) {
            System.out.println("Invalid input");
        }
    }
}

运行示例：

Enter the day: wednesday
[WEDNESDAY, THURSDAY, FRIDAY, SUNDAY, MONDAY, TUESDAY]

Answer 2

我建议使用类似于以下的方法：

在Java中如何将数组值排序为循环格式？

其中每个dayofweek都有自己的ID号，它对应于其预定的顺序位置，因此您可以围绕这些数字旋转。