如何用seperator更新YML文件

Question

nlu:
- intent: greet
  examples: |
    - hey
    - hello
    - hi
    - hello there

with open('nlu.yml', 'r') as yamlfile:
    cur_yaml = yaml.safe_load(yamlfile)
    cur_yaml['nlu'].append({ 'intent': 'name', 'examples': ['first', 'second']})

with open('nlu.yml', 'w') as yamlfile:
     yaml.safe_dump(cur_yaml, yamlfile)

Answer 1

不是分隔符。它是块标量的头，这意味着examples的值是一个标量，其内容为“-hey\n-hello\n-hi\n-hello there\n”。若要追加具有相同语义结构的另一序列项，您需要执行以下操作：

with open('nlu.yml', 'r') as yamlfile:
    cur_yaml = yaml.safe_load(yamlfile)
    cur_yaml['nlu'].append({ 'intent': 'name', 'examples': "- first\n- second\n"})

完整的工作示例：

import yaml, sys

input = """
nlu:
- intent: greet
  examples: |
    - hey
    - hello
    - hi
    - hello there
"""

cur_yaml = yaml.safe_load(input)
cur_yaml['nlu'].append({ 'intent': 'name', 'examples': "- first\n- second"})

yaml.safe_dump(cur_yaml, sys.stdout)

这一输出

nlu:
- examples: '- hey

    - hello

    - hi

    - hello there

    '
  intent: greet
- examples: '- first

    - second

    '
  intent: name

append_to_yaml("input.yaml", "output.yaml", [
  AppendableEvents(["nlu"],
    [MappingStartEvent(None, None, True), key("intent"), key("name"),
     key("examples"), literal_value("- hello there\n- general Kenobi\n"),
     MappingEndEvent()])])

nlu:
- intent: greet
  examples: |
    - hey
    - hello
    - hi
    - hello there
- intent: name
  examples: |
    - hello there
    - general Kenobi